A)Ep'=mgh=mgl(1-cosa).At the bottom of the swing Ep=0(reference level),so the potential energy as the child is just released is bigger than the potential energy at the bottom of the swing.;B)The speed of the child at the bottom of the swing-->v=√(2gh)=√[2gl(1-cosa)];C)I don't think that the tension does any work.
Answer:
OA. . review all safety procedures and the lab activity procedure
Explanation:
Answer:
Answer for the question is given in the attachment.
Explanation:
The centripetal force is force acting on a body in circular motion. In circular motion, velocity is always on tangent and if we took 2 different positions on a circle, the change on velocity is a vector pointing in the middle of circle. In circular motion velocity is constant, and acceleration lies on radius of circle pointing to te middle. This acceleration is called centripetal acceleration, and the force is centripetal.
