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3 years ago

9

Which of the numbers below is less than 14.76? Select all that apply.

2 answers:

frosja888 [35]3 years ago

8 0

Answer:

A & D

Step-by-step explanation:

marissa [1.9K]3 years ago

4 0

The answers are A and D!!

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OlgaM077 [116]

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3 years ago

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Rhonda has $4.85 in coins. If she has six more nickels than dimes and twice as many quarters as dimes, how many coins of each ty

Novay_Z [31]

Answer: nickels = 13, dimes = 7, quarters = 14

<u>Step-by-step explanation:</u>

First, set up the equations for each coin:

$\begin {array}{c|c|c|l}\underline{\quad Type\quad }&\underline{Value}&\underline{Quantity}&\underline{\qquad \qquad \qquad Equation\qquad }\\ Nickel& \$0.05&6+d&0.05(6+d) = 0.30 + 0.05d\\Dime& \$0.10&d&\qquad 0.10(d)=0.10d\\Quarter& \$0.25&2d&\qquad 0.25(2d)=0.50d\\\end{array}$

Next, the sum of the coins is $4.85 so substitute and solve for the variable:

Nickels + Dimes + Quarters = Sum

(0.30 + 0.05d) + 0.10d + 0.50d = 4.85

0.30 + 0.65d = 4.85

0.65d = 4.55

d = 7

Lastly, plug the d-value into the quantity equation for the nickels and quarters to find their quantity.

nickels: 6 + d = 6 + (7) = 13

quarters: 2d = 2(7) = 14

6 0

3 years ago

I just need someone to fill in all the answers

Masteriza [31]

Answer:

1. 2

2. 25

3. 1/3

I'm in 8th grade so not 100% sure about these

I'm gonna try the rest

But this is what I got so far!

3 0

3 years ago

Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 217

Soloha48 [4]

Answer:

$f(216) \approx 6.0093$

Step-by-step explanation:

Given

$\sqrt[3]{217}$

Required

Solve

Linear approximated as:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

Take:

$x = 216; \triangle x= 1$

So:

$f(x) = \sqrt[3]{x}$

Substitute 216 for x

$f(x) = \sqrt[3]{216}$

$f(x) = 6$

So, we have:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

$f(215 + 1) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot f'(x)$

To calculate f'(x);

We have:

$f(x) = \sqrt[3]{x}$

Rewrite as:

$f(x) = x^\frac{1}{3}$

Differentiate

$f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}$

Split

$f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}$

$f'(x) = \frac{x^\frac{1}{3}}{3x}$

Substitute 216 for x

$f'(216) = \frac{216^\frac{1}{3}}{3*216}$

$f'(216) = \frac{6}{648}$

$f'(216) = \frac{3}{324}$

So:

$f(216) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot \frac{3}{324}$

$f(216) \approx 6 + \frac{3}{324}$

$f(216) \approx 6 + 0.0093$

$f(216) \approx 6.0093$

6 0

3 years ago