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Ulleksa [173]
3 years ago
14

Which expression is represented by the diagram?

Mathematics
1 answer:
Vilka [71]3 years ago
6 0
-6-(-1)

explanation:
-6-(-1)
remove parentheses
-6+1=5
there are only 5 blocks remaining and this equation is the only one that totals out to 5 blocks
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How many times does 12 go into 80 the times you have done 12 into 80 is when you count to 12 or 80 or do 80 or 12 jumping jacts
JulijaS [17]
80÷12= 6 2/3

12×12×12×12×12×12=72

so 12 goes into 80 evenly 6 times, but there is a remainder so you have to include it

80-72=8
so that leaves you with 8/12 which is 2/3 when simplified

now you have 6 + 2/3 = 6 2/3
4 0
3 years ago
Determain the equation, in slope intercept form, of the line of the line that has a slope of -6 and passes through the point P(-
Vinil7 [7]

Answer:

<h2>         y = -6x - 16</h2>

Step-by-step explanation:

The point-slope form of the equation is y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope:

m = -6

(-3, 2)    ⇒   x₀ = -3,  y₀ = 2

The point-slope form of the equation:

y - 2 = -6(x + 3)

So:

y - 2 = -6x - 18         {add 2 to both sides}

y = -6x - 16             ←  the slope-intercept form of the equation

5 0
2 years ago
Find the zeros and verify x^2 +2x-180
Arada [10]

Answer:

Rounded to the nearest tenth they are -14.5 and 12.5

Step-by-step explanation:

The zeros of a function are the x-intercepts or roots where the function crosses the x-axis. To find them, graph the function x^2 +2x-180 and zoom in on the x-axis.

See attached picture.

6 0
3 years ago
Plz help whith homework
grin007 [14]
You have to turn the denominators the same then whatever you do to the top you do to the bottom the just subtract
6 0
3 years ago
Which statement is true about the discontinuities of the function f(x) = x-5/3x^2-17x-28
o-na [289]
1) function f(x)

              x - 5
f(x) = ----------------
          3x^2 - 17x - 28

2) factor the denominator:

3x^2 - 17x  - 28 = (3x + 4)(x - 7)

                        x - 5
=> f(x) = -----------------------
                (3x + 4) (x  - 7)

3) Find the limits when x → - 4/3 and when x → 7

Lim of f(x) when x → - 4/3 = +/- ∞

=> vertical assymptote x = - 4/3

Lim of f(x) when x → 7 = +/- ∞

=> vertical assymptote x = 7

Answer: there are assympotes at x = 7 and x = - 4/3
6 0
3 years ago
Read 2 more answers
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