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3 years ago

13

Meg collects coins from other countries. After her mother gives her 8 coins, Meg has a total of 27 coins in her collection. How

many coins did she start with?

2 answers:

Katarina [22]3 years ago

5 0

Meg started with 19 coins.
Do 27-8 to get 19.

Gekata [30.6K]3 years ago

3 0

The correct answer is 19 coins
You take 27-8 which equal 19. Hope this helps!

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Point S is on line segment \overline{RT}

Semenov [28]

Answer:

RT = 20

Step-by-step explanation:

Point S is on line segment

R------------S------------T

RS + ST = RT

Given

ST=3x-8

RT=4x

RS=4x-7,

Step 1

We find x

4x - 7 + 3x - 8 = 4x

4x + 3x -7 - 8 = 4x

7x - 15 = 4x

7x - 4x = 15

3x = 15

x = 15/3

x = 5

Step 2

We find RT

RT = 4x

x = 5

RT = 4 × 5

RT = 20

The numerical length of RT is 20

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A person creates a game in which a person pays $5.00 to play. Then, they draw a single card from a standard shuffled deck of car

valkas [14]

Answer:

Step-by-step explanation:

The expected value is the probability of an event multiplied by the number of times the event happens. And if there is more than 1 event, the expected value is the sum of those.

There are 52 cards in a deck.

There are 12 face cards in a deck. (gain 10)

There are 4 ace in a deck. (gain 20)

Any other card is 36 of them. (lose 5)

The probability of face card is 12/52

The probability of ace is 4/52

The probability of any other card is 36/52

Thus the expected values is:

(12/52)(10) + (4/52)(20) + (36/52)(-5) = $0.38

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3 years ago

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Choose the numbers that are terminating decimals. Select all that apply.

horsena [70]

Answer: A, C, and D

Step-by-step explanation:

A terminating decimal is a decimal that has an end. In other words, $\frac{1}{4} =0.25$ is one, but $\frac{1}{3} =0.3333...$ is not.

✓ A. 0.032

✗ B. 0.999...

✓ C. 0.525

✓ D. 0.75

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1 year ago

Five Stars and Brainliest To Correct Answer

Westkost [7]

The correct answer is x = 1/28y^2

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3 years ago

NO LINKS OR FILES!

Archy [21]

(a) If the particle's position (measured with some unit) at time <em>t</em> is given by <em>s(t)</em>, where

$s(t) = \dfrac{5t}{t^2+11}\,\mathrm{units}$

then the velocity at time <em>t</em>, <em>v(t)</em>, is given by the derivative of <em>s(t)</em>,

$v(t) = \dfrac{\mathrm ds}{\mathrm dt} = \dfrac{5(t^2+11)-5t(2t)}{(t^2+11)^2} = \boxed{\dfrac{-5t^2+55}{(t^2+11)^2}\,\dfrac{\rm units}{\rm s}}$

(b) The velocity after 3 seconds is

$v(3) = \dfrac{-5\cdot3^2+55}{(3^2+11)^2} = \dfrac{1}{40}\dfrac{\rm units}{\rm s} = \boxed{0.025\dfrac{\rm units}{\rm s}}$

(c) The particle is at rest when its velocity is zero:

$\dfrac{-5t^2+55}{(t^2+11)^2} = 0 \implies -5t^2+55 = 0 \implies t^2 = 11 \implies t=\pm\sqrt{11}\,\mathrm s \imples t \approx \boxed{3.317\,\mathrm s}$

(d) The particle is moving in the positive direction when its position is increasing, or equivalently when its velocity is positive:

$\dfrac{-5t^2+55}{(t^2+11)^2} > 0 \implies -5t^2+55>0 \implies -5t^2>-55 \implies t^2 < 11 \implies |t|$

In interval notation, this happens for <em>t</em> in the interval (0, √11) or approximately (0, 3.317) s.

(e) The total distance traveled is given by the definite integral,

$\displaystyle \int_0^8 |v(t)|\,\mathrm dt$

By definition of absolute value, we have

$|v(t)| = \begin{cases}v(t) & \text{if }v(t)\ge0 \\ -v(t) & \text{if }v(t)$

In part (d), we've shown that <em>v(t)</em> > 0 when -√11 < <em>t</em> < √11, so we split up the integral at <em>t</em> = √11 as

$\displaystyle \int_0^8 |v(t)|\,\mathrm dt = \int_0^{\sqrt{11}}v(t)\,\mathrm dt - \int_{\sqrt{11}}^8 v(t)\,\mathrm dt$

and by the fundamental theorem of calculus, since we know <em>v(t)</em> is the derivative of <em>s(t)</em>, this reduces to

$s(\sqrt{11})-s(0) - s(8) + s(\sqrt{11)) = 2s(\sqrt{11})-s(0)-s(8) = \dfrac5{\sqrt{11}}-0 - \dfrac8{15} \approx 0.974\,\mathrm{units}$

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2 years ago