Question

Point B has coordinates ​(3​,1​). The​ x-coordinate of point A is negative 1. The distance between point A and point B is 5 units. What are the possible coordinates of point​ A?

Answer 1

Answer:

Given in quesion:Point B (3,1) and point A is -1. Distance between A and B is 5 units.

Using distance formula for AB we obtain,

AB^2=(x2-x1)^2 + (y2-y1)^2

5^2=(3+1)^2 + (1-y)^2

25-16=(1-y)^2

9=(1-y)^2

1-y=3

y= -2

Therefore the possible co-ordinates of A are(-1,-2).This is your required answer.