Assume N students
Student 1 can get (n-1) papers
Student 2 can get (n-1) papers
Student 3 can get (n-1) papers
etc
Student N can get (n-1) papers
So for N students you can have N(n-1)
1. You would set them up:46+7
2. Next you would do 6+7 which equals 13
3. You would then bring down the 4
4. And last you get the answer:53
Hope this helped you!
7/9 is the answer I believe
Answer:
for every rise of 1 the run would be 25
Answer:
h= 62 g=118
Step-by-step explanation:
