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Alenkinab [10]
3 years ago
6

Please Help! Write a equation for each hanger!

Mathematics
1 answer:
julsineya [31]3 years ago
7 0

Answer:

Step-by-step explanation:

A: 2x = 3

B: w+1.3 = 2.7

C: 3y = 5.1

D: z+⅓ = ½

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Carly's age is more than twice his sisters age, s. Which of the following expressions represents Carly's age? (A) 2s + 3 (B) 3s
Ilya [14]
I would say A.

B would be Carly's age is two years more than three times his sister's age.

C would be Carly's age is two times his sister's age plus three

D would be Carly's age is his sister's age squared plus three.
5 0
3 years ago
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What is the slope of the line that passes through the points (1, -2) and (3, -5)?
Ksivusya [100]

Slope of the line is -3/2

Step-by-step explanation:

  • Step 1: Given points are (1, -2) and (3, -5)
  • Step 2: Equation for slope, m = (y2 - y1)/(x2 - x1)

⇒ m = (-5 - -2)/(3 - 1) = -3/2

4 0
3 years ago
a car purchased for $34,000 is expected to lose value, or depreciate, at a rate of 6% per year.using x for years and y for the v
Vika [28.1K]

Answer:

y = 34000(1-0.06) ^ t

After 7.40 years it will be worth less than 21500

Step-by-step explanation:

This problem is solved using a compound interest function.

This function has the following formula:

y = P(1-n) ^ t

Where:

P is the initial price = $ 34,000

n is the depreciation rate = 0.06

t is the elapsed time

The equation that models this situation is:

y = 34000(1-0.06) ^ t

Now we want to know after how many years the car is worth less than $ 21500.

Then we do y = $ 21,500. and we clear t.

21500 = 34000(1-0.06) ^ t\\\\log(21500/34000) = tlog(1-0.06)\\\\t = \frac{log(21500/34000)}{log(1-0.06)}\\\\t = 7.40\ years.

After 7.40 years it will be worth less than 21500

3 0
3 years ago
Subtract 1/6a+3 from 1/3a−5<br> PLZ HELP ASAP
lukranit [14]

Answer:

1/3a - 5 - (1/6a + 3) =

1/3a - 5 - 1/6a - 3 =

1/3a - 1/6a - 5 - 3 =

2/6a - 1/6a - 8 =

1/6a - 8 <===

Step-by-step explanation:

5 0
3 years ago
Please help this is due tomorrow
Masteriza [31]

Answer:

Step-by-step explanation:

Maybe this will help



4 0
2 years ago
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