Answer:
(14,4) (21, 6) (28,8) If they had six losses, they would have 21 wins
Step-by-step explanation:
According to the information given, for every 7 wins, they lose 2 games. That means in order to finish the table, we have to find multiples of 7 and 2. If they won 14 games, they would have 4 losses. This is because since 14 is twice the value of 7, they would have lost twice the number of games.
The next would be 21 wins since 7x3 is 21 and 6 losses since 2x3 is 6
The last one would be 28 wins (7x4) and 8 losses (2x4)
If they had six losses, they would have 21 wins
I belive the answer is 240 because there are 4 C in a L so what I did was 4×60 and I got 240 cups
I can't tell you the answer but I can tell you what to do. First you have to take what is in parentheses first. x-4... But I think you made this up because your not supposed to put 10× but the 8(x-4) that makes sense but the last part doesn't..
2x - 3 < 11 or 8x -10 < 82: <span>X < 23/2
<span>
Part 1</span>
</span>2x-3<11
Add 3 both sides
2x-3+3<11+3
Refine
2x<14
Divide by 2 on both sides
2x / 2 / 14 / 2
Refine
x < 7
<span>
Part 2</span>
8x-10<82
Add 10 to both sides
8x-10+10<82+10
Refine
8x<92
Divide by 8
8x / 8 / 92 / 8
Refine
x < 23 / 2
