1.25
hope it helped and sorry if it's wrong i wish you luck
is there more to the question? because in order find "s" I need to know the question but a majority of the time you would multiply the amount of money the suit cost by the quantity.
Im a math intern.
Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.
For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- There are 9 rolls, hence
.
- Of the six sides, 2 are 3 or 4, hence

The desired probability is:

In which:

Then



Then:


0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.
For more on the binomial distribution, you can check brainly.com/question/24863377
Answer:
A biconditional statement is a combination of a conditional statement Its converse written in the if and only form
The period of a sinusoid

is

, so any range such that

will give two complete periods.