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faltersainse [42]
3 years ago
6

What are the atomic letters for gold?

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
6 0
Au, and of course the best faction is caesar's legion! No competion.
Lunna [17]3 years ago
3 0

Answer:

No its the Enclave

Step-by-step explanation:

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What is the Question so I can answer?

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Solve the equation below:
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\sqrt[3]{x^2-8}=2 \\ x^2-8=2^3=8  \\ x^2=16 \\  \\ \boxed{x=4 \ or \ -4}
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An acid is a substance that increases the concentration of H3O+ ions in solution. Look at the reaction below of phenol (C6H5OH)
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Answer:

The reactant that acts as an acid, by contributing an H⁺ ion to create H3O+ in the chemical equation is C₆H₅OH.

Step-by-step explanation:

According to Brønstend-Lowry, an acid is a substance that transfer a proton (hydrogen cation, H⁺) to a base, forming a base conjugate for the first and an acid conjugate for the second.      

From the following reaction:

C₆H₅OH(aq) + H₂O(l)  →  C₆H₅O⁻(aq) + H₃O⁺(aq)

   

We have that the C₆H₅OH transfer a proton to the water to form its conjugate base C₆H₅O⁻ and the conjugate acid of water H₃O⁺. Hence, the C₆H₅OH is the acid and the water is the base.

Therefore, the reactant that acts as an acid, by contributing an H⁺ ion to create H3O+ in the chemical equation is C₆H₅OH.

I hope it helps you!

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3 years ago
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Csc (2sin^-1(-12/13))<br> that is 2 times inverse sin of -12/13
german
Answer: -\frac{169}{120}

I'm assuming you mean this:

cosec(2sin^{-1}(\frac{-12}{13}))

Recall what the cosecant function represents. It is the reciprocal of a sine function, and is often written in this form:

\frac{1}{sinx}

So, using the sine relationship:

cosec(2sin^{-1}(\frac{-12}{13})) = \frac{1}{sin(2sin^{-1}(\frac{-12}{13}))}

Let u = sin^{-1}(\frac{-12}{13})
cosec(2sin^{-1}(\frac{-12}{13})) = \frac{1}{sin(2u)}
= \frac{1}{2sinu \cdot cosu}
= \frac{1}{2sin(sin^{-1}(\frac{-12}{13})) \cdot cos(sin^{-1}(\frac{-12}{13}))}
= \frac{1}{\frac{-24}{13} \cdot \sqrt{1 - (\frac{-12}{13})^{2}}}
= \frac{1}{\frac{-24}{13}} \cdot \frac{1}{\sqrt{1 - \frac{144}{169}}}
= -\frac{13}{24} \cdot \frac{1}{\sqrt{\frac{25}{169}}}
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