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Juli2301 [7.4K]
2 years ago
10

amir rented a dvd and it was due to be returned on 28 march he actually returned it to the shop on 16 april the rental shop appl

ies 7p for everyday the dvd is overdue. Work out the total fine paid by amir give your answer in £
Mathematics
1 answer:
Gre4nikov [31]2 years ago
4 0

Answer:

£133

Step-by-step explanation:

March had 31 days

Extra days used in March = March 31 - March 28

= 3 days

Extra days used in April = 16 days

Total extra days used = Extra days used in March + Extra days used in April

= 3 days + 16 days

= 19 days

Cost per extra days = £7

Total fine for 19 extra days = £7 × 19

= £133

Total fine paid = £133

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A line with a slope -2 passes through the point (-1,4). Which equation represents this line in point-slope form?
sesenic [268]

9514 1404 393

Answer:

  y-4 = -2(x+1)

Step-by-step explanation:

The point-slope equation of a line is ...

  y -k = m(x -h) . . . . . line with slope m through point (h, k)

You have m = -2 and (h, k) = (-1, 4). Putting these numbers into the above form gives ...

  y -4 = -2(x +1)

7 0
3 years ago
In one region, the september energy consumption levels for single-family homes are found to be normally distributed with a mean
tatyana61 [14]
The probability would be 0.1971.

We will calculate a z-score for each end of this interval.

z = (X-μ)/σ

For the lower limit:
z = (1100-1050)/218 = 50/218 = 0.23

For the upper limit:
z = (1225-1050)/218 = 175/218 = 0.80

Using a z-table (http://www.z-table.com) we see that the area under the curve to the left of, less than, the lower limit is 0.5910.  The area under the curve to the left of, less than, the upper limit is 0.7881.  To find the area between them, we subtract:

0.7881 - 0.5910 = 0.1971
6 0
3 years ago
Read 2 more answers
Five miles Equals to how many feet
Luba_88 [7]
5 miles is 26400 feet.
6 0
3 years ago
Read 2 more answers
The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 30 mm and standard d
skelet666 [1.2K]

Answer:

z=-0.842

And if we solve for a we got

a=30 -0.842*7.8=23.432

So the value of height that separates the bottom 20% of data from the top 80% is 23.432.  

Step-by-step explanation:

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(30,7.8)  

Where \mu=30 and \sigma=7.8

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.80   (a)

P(X   (b)

As we can see on the figure attached the z value that satisfy the condition with 0.20 of the area on the left and 0.80 of the area on the right it's z=-0.842

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.842

And if we solve for a we got

a=30 -0.842*7.8=23.432

So the value of height that separates the bottom 20% of data from the top 80% is 23.432.  

8 0
3 years ago
I need help please it’s really hard and I don’t understand it
mr_godi [17]

The line segment HI has length 3<em>x</em> - 5, and IJ has length <em>x</em> - 1.

We're told that HJ has length 7<em>x</em> - 27.

The segment HJ is made up by connecting the segments HI and IJ, so the length of HJ is equal to the sum of the lengths of HI and IJ.

This means we have

7<em>x</em> - 27 = (3<em>x</em> - 5) + (<em>x</em> - 1)

Solve for <em>x</em> :

7<em>x</em> - 27 = (3<em>x</em> + <em>x</em>) + (-5 - 1)

7<em>x</em> - 27 = 4<em>x</em> - 6

7<em>x</em> - 4<em>x</em> = 27 - 6

3<em>x</em> = 21

<em>x</em> = 21/3

<em>x</em> = 7

5 0
3 years ago
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