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Dima020 [189]
3 years ago
15

What is the smallest degree of rotation that will map a regular 18 gon on to itself

Mathematics
1 answer:
natali 33 [55]3 years ago
5 0

Answer:

  20°

Step-by-step explanation:

Rotating the figure through an angle equal to the central angle of one "sector" will do the required mapping. That is 360°/18 = 20°.

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How do you think you could simplify f(x) + g(x) if f(x) = 3x + 2 and g(x) = 4x?
NARA [144]

Step-by-step explanation:

f(x) = 3x + 2

g(x) = 4x

= f(x) + g(x)

= 3x + 2 + 4x

= (3 + 4)x + 2

= 7x + 2

(f+g)(x) = 7x + 2

7 0
2 years ago
Given that f(x) = x2 – 3x - 10 and g(x) = x – 5, find (f - g)(x) and express
Roman55 [17]

Answer:

(f-g)(x)= x^2-4x-5

Step-by-step explanation:

We have the two functions:

f(x)=x^2-3x-10\text{ and } g(x)=x-5

And we want to find (f-g)(x).

(f-g)(x) is equivalent to f(x)-g(x).

Therefore:

\begin{aligned} (f-g)(x)&=f(x)-g(x)\\ &=(x^2-3x-10)-(x-5)\end{aligned}

Simplify:

\begin{aligned} &=x^2-3x-10-x+5 \\ &=(x^2)+(-3x-x)+(-10+5) \\ &=x^2-4x-5\end{aligned}

Therefore:

(f-g)(x)= x^2-4x-5

8 0
2 years ago
Read 2 more answers
According to a​ survey, 65​% of murders committed last year were cleared by arrest or exceptional means. Fifty murders committed
monitta

Answer:

a) P(X=41)=(50C41)(0.65)^{41} (1-0.65)^{50-41}=0.00421

b) P(X=36)=(50C36)(0.65)^{36} (1-0.65)^{50-36}=0.0714

P(X=37)=(50C37)(0.65)^{37} (1-0.65)^{50-37}=0.0502

P(X=38)=(50C38)(0.65)^{38} (1-0.65)^{50-38}=0.0319

And adding these values we got:

P(36 \leq X \leq 38)= 0.1535

c) We can find the expected value given by:

E(X) = np =50*0.65 = 32.5

And the standard deviation would be:

\sigma = \sqrt{np(1-p)} \sqrt{50*0.65*(1-0.65)}= 3.373

We can use the approximation to the normal distribution and we have at leat 95% of the data within 2 deviations from the mean. And the lower limit for this case would be:

\mu -2\sigma = 32.5- 2*3.373 = 25.75

And then we can consider a value of 18 as unusual lower for this case.

Step-by-step explanation:

Let X the random variable of interest "number cleared by arrest or exceptional", on this case we can model this variable with this distribution:

X \sim Binom(n=50, p=0.65)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

We want this probability:

P(X=41)=(50C41)(0.65)^{41} (1-0.65)^{50-41}=0.00421

Part b

We want this probability:

P(36 \leq X \leq 38)

We can find the individual probabilities:

P(X=36)=(50C36)(0.65)^{36} (1-0.65)^{50-36}=0.0714

P(X=37)=(50C37)(0.65)^{37} (1-0.65)^{50-37}=0.0502

P(X=38)=(50C38)(0.65)^{38} (1-0.65)^{50-38}=0.0319

And adding these values we got:

P(36 \leq X \leq 38)= 0.1535

Part c

We can find the expected value given by:

E(X) = np =50*0.65 = 32.5

And the standard deviation would be:

\sigma = \sqrt{np(1-p)} \sqrt{50*0.65*(1-0.65)}= 3.373

We can use the approximation to the normal distribution and we have at leat 95% of the data within 2 deviations from the mean. And the lower limit for this case would be:

\mu -2\sigma = 32.5- 2*3.373 = 25.75

And then we can consider a value of 18 as unusual lower for this case.

6 0
3 years ago
A group of students are planning a mural at a wall the rectangular wall has dimensions of (6x+7) by (8x+5) and they are planning
zvonat [6]

Answer: 46x^2+73x+15

Step-by-step explanation:

The area of a rectangle can be calculated with the formula:

A=lw

l: the length of the rectangle.

w: the width of the rectangle.

The area of the remaning wall after the mural has been painted, will be the difference of the area of the wall and the area of the mural.

Knowing that the dimensions of the wall are (6x+7) by (8x+5), its area is:

A_w=(6x+7)(8x+5)\\\\A_w=48x^2+30x+56x+35\\\\A_w=48x^2+86x+35

As they are planning that the dimensions of the mural be (x+4) by (2x+5), its area is:

A_m=(x+4)(2x+5)\\\\A_m=2x^2+5x+8x+20\\\\A_m=2x^2+13x+20

Then the area of the remaining wall after the mural has been painted is:

A_{(remaining)}=A_w-A_m\\\\A_{(remaining)}=48x^2+86x+35-(2x^2+13x+20)\\\\A_{(remaining)}=48x^2+86x+35-2x^2-13x-20\\\\A_{(remaining)}=46x^2+73x+15

8 0
3 years ago
A RECTANGULAR PRISM HAS A VOLUME OF 96 FT. THE AREA OF THE BASE IS 24 FT. WHAT IS THE HEIGHT OF THE PRISM?
Reptile [31]
96
i hope it is right answer ;)
6 0
3 years ago
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