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Oliga [24]
3 years ago
5

Which of the following pairs of events are mutually exclusive? Rolling a die; A={Rolling an even number}, B={Rolling a number gr

eater than 4} Picking a card; A= {Selecting a 7}, B={Selecting a Heart} Tossing a coin twice; A ={no Heads}, B={at least 1 Head} Rolling two 6-sided dice; A={rolling a sum of 4}, B={rolling a 3 on one die}
Mathematics
1 answer:
choli [55]3 years ago
6 0

Answer:

Tossing a coin twice; A ={no Heads}, B={at least 1 Head}

Step-by-step explanation:

Mutually exclusive:

If two events are mutually exclusive, if one events happen, the other cannot happen, and vice-versa.

Rolling a die; A={Rolling an even number}, B={Rolling a number greater than 4}

A die has the following outcomes: 1,2,3,4,5,6

Even numbers: 2,4,6

Greater than 4: 5, 6

6 is an outcome of both events A and B, so they are not mutually exclusive.

Picking a card; A= {Selecting a 7}, B={Selecting a Heart}

Cards numbered from 1 to 13, each number with 4 types. So we can have a card of hearts numbered 7, which means that these events are not mutually exclusive.

Tossing a coin twice; A ={no Heads}, B={at least 1 Head}

If you get no heads, the probability of at least 1 head is 0.

If you get at least 1 head, the probability of no heads is 0.

This means that this is the answer, that is, these events are mutually exclusive.

Rolling two 6-sided dice; A={rolling a sum of 4}, B={rolling a 3 on one die}

(3,1) or (1,3) has a sum of 4 and a 3 on one die, which means that these events are not mutually exclusive.

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y=8 \cdot (\frac{5}{4})^x

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or

f(x)=8 \cdot (1.25)^x

Step-by-step explanation:

We are going to see if the exponential curve is of the form:

y=a \cdot b^x, (b\neq 0).

If you are given the y-intercept, then a is easy to find.

It is just the y-coordinate of the y-intercept is your value for a.

(Why? The y-intercept happens when x=0. Replacing x with 0 gives y=a \cdot b^0=a \cdot 1=a. This says when x=0 \text{ that} y=a.)

So a=8.

So our function so far looks like this:

y=8 \cdot b^x

Now to find b we need another point. We have two more points. So we will find b using one of them and verify for our resulting equation works for the other.

Let's do this.

We are given (1,10) is a point on our curve.

So when x=1, y=10.

10=8 \cdot b^1

10=8 \cdot b

Divide both sides by 8:

\frac{10}{8}=b

Reduce the fraction:

\frac{5}{4}=b

So the equation if it works out for the other point given is:

y=8 \cdot (\frac{5}{4})^x

Let's try it.  So the last point given that we need to satisfy is (2,12.5).

This says when x=2, y=12.5.

Let's replace x with 2 and see what we get for y:

y=8 \cdot (\frac{5}{4})^2

y=8 \cdot \frac{25}{16}

y=\frac{8}{16} \cdot 25

y=\frac{1}{2} \cdot 25}

y=\frac{25}{2}

y=12.5

So we are good. We have found an equation satisfying all 3 points given.

The equation is y=8 \cdot (\frac{5}{4})^x.

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