Now that we’ve learned how to solve word problems involving the sum of consecutive integers, let’s narrow it down and this time, focus on word problems that only involve finding the sum of consecutive even integers.
But before we start delving into word problems, it’s important that we have a good understanding of what even integers, as well as consecutive even integers, are.
Even Integers
We know that even numbers are integers that can be divided exactly or evenly by 22. Thus, the general form of the even integer nn, is n = 2kn=2k, where kk is also an integer.
In other words, since even numbers are the multiples of 22, we can represent an even integer nn by 2k2k, where kk is also an integer. So if we have the even integers 1010 and 1616,
Answer:
Below
Step-by-step explanation:
9 
Step-by-step explanation:
To write 5 as a fraction with a common denominator, multiply by 55 . Combine 5 and 55 . Combine the numerators over the common denominator. Simplify the numerator.
Each individual contributed $x
3x=$19.50
x=$6.50
Each friend contributed $6.50
Answer:
V ≈ 3367.6 cm³
Step-by-step explanation:
The volume (V) of a sphere is calculated as
V = 
πr³ ( r is the radius )
Here D = 18.6 , then r = 18.6 ÷ 2 = 9.3 , so
V = × 3.14 × 9.3³
= × 3.14 × 804.357
= 
≈ 3367.6 cm³ ( to the nearest tenth )
