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Vladimir79 [104]

3 years ago

14

Please help!

2 answers:

Musya8 [376]3 years ago

5 0

Answer:

C. $-6x-2y=12$

Step-by-step explanation:

We are given that a graph.

We have to find the equation of given graph.

The line passes through the point (-2,0) and (0,-6).

Slope:m $=\frac{y_2-y_1}{x_2-x_1}$

By using the formula

$m=\frac{-6-0}{0+2}=-3$

Slope-intercept form: $y=mx+C$

Where m=Slope of line

C=y-intercept

y-intercept: It is that value of y for which x=0

We have y- intercept=-6

Using the formula

Equation of line

$y=-3x-6$

$3x+y=-6$

Multiply by -2 on both sides then we get

$-6x-2y=12$

dezoksy [38]3 years ago

3 0

Answer:

Answer 3 (-6x-2y=12)

Step-by-step explanation: Turn to slope form to check

First- Add the 6x from both sides

-2y=6x+12

Second- Divide by two on both sides

y= -3x-6

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2 years ago

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

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Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

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Solve for $u$ :

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$\dfrac2{u+1}=1-Ce^{2t}$

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Now use the given initial condition to solve for $C$ :

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Step-by-step explanation:

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Step-by-step explanation:

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