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Aleksandr [31]
3 years ago
8

Using the extreme value theorem, which graph has a maximum of 3 and minimum of –9?

Mathematics
2 answers:
klasskru [66]3 years ago
7 0

Answer:

the 1st one

Step-by-step explanation:

soldi70 [24.7K]3 years ago
7 0

Answer:

A

Step-by-step explanation:

Right on edge

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A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
Which term best describes the system of equations?
Oduvanchick [21]

Answer:

  coincident

Step-by-step explanation:

The first equation is 3 times the second equation, so describes exactly the same line. The lines are "coincident".

7 0
3 years ago
Put the numbers in order from least to greatest.
butalik [34]
None of the answers are correct because it would be 4, 10, 12, 17, then 41
3 0
3 years ago
62+7h in word phrase
Nadya [2.5K]

Answer:

sixty-two plus 7 times a number h

Step-by-step explanation:

6 0
3 years ago
Suppose j varies jointly with g and v, and j=1 when g=6 and v=3.
Alex_Xolod [135]
"Joint variation<span>" means "directly, but with two or more variables". Thus, we write as follows:

j </span>α gv
<span>
We insert proportionality constant k, to change it to equality.

j = kgv

We solve k,

1 = k (4)(3)
k =1/12

j = gv/12
j = 8(11)/12
j = 22/3</span>
6 0
3 years ago
Read 2 more answers
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