If x + 2y = 1, and 2x + y = 5, then x + y = ?

Mathematics

1 answer:

solmaris [256]3 years ago

6 0

I’m pretty sure it’s A

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Every year, the value of a property in singapore appreciates by 15% of its value in the previous year. If the value of the prope

tensa zangetsu [6.8K]

Answer:

629 510$

Step-by-step explanation:

$899300 - (30% of $899300)

cuz its two years away from 2010 so it will have gone up 30 % so to rewind time, just go back 30%

4 0

3 years ago

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HELP PLS i’ll mark as brainliest if correct

Vlada [557]

Answer:

I believe the answer is the second one

Step-by-step explanation:

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3 years ago

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Leno4ka [110]

Answer:

$\frac{s^2-25}{(s^2+25)^2}$

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given: $\mathcal{L}[t \cos 5t]=(-1)F'(s)$ with $F(s)=\mathcal{L}[\cos 5t]$ .

Now, $F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt$ . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that $F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt$ .

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

$F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s)$ .