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2 years ago

What is the value of x

Mathematics

2 answers:

ra1l [238]2 years ago

3 0

Answer:

The value of x is dependant on the value of y.

Step-by-step explanation:

y = (number)x + (another number)

I need a PNG or picture to give you a factual answer to the value of X.

kotegsom [21]2 years ago

3 0

What the guy above me said is correct

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lukranit [14]

Answer:

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3 years ago

Summarize what is a stock?

Naya [18.7K]

Answer:

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Step-by-step explanation:

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3 years ago

Un número desconocido es multiplicado por 11 y a este resultado se le resta 24. El resultado de esta operación es 86. Escribe en

kicyunya [14]

Answer: The number is 10.

Step-by-step explanation:

Let x be the required number.

Given: 11 is multiplied to the number then 24 is subtracted from that and the result is 86.

The mathematical statement for the given situation,

11x -24 = 86

To solve the equation, Add 24 on both sides , we get

11x - 24 +24 = 86+24

⇒ 11x = 110

Divide both sides by 11, we get

x = 10

hence, the number is 10.

3 0

3 years ago

A fisherman positions his net to -8 relative to the surface of the water. how far does he need to raise the net to bring it to t

8_murik_8 [283]

Answer: If i am correct the answer should be 9-10 because if it is -8 it takes 8 to bring it to 0 and it takes 9 to bring it to 1 and it takes 10 to bring it to 2.

Hope this helps!

6 0

3 years ago

A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set

lara [203]

A circle with center $(3,0)$ and radius $5$ has equation

$(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x = 16$

If we substitute $y=2x+k$ in this equation, we have

$x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0$

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

$\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0$

The expression simplifies to

$-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89$

The solutions to the associated equation are

$k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}$

So, the parabola is negative between the two solutions:

$-6-5\sqrt{5}$

8 0

3 years ago