Ask question

Ask question

All categories

3 years ago

14

The area of a rectangle is 12 square units. If the length and width of the rectangle are both enlarged by a factor of 3, which o

f the following can be used to determine the area of the new rectangle?

1 answer:

kirill [66]3 years ago

7 0

Answer:

3/2 (12)

Step-by-step explanation:

You might be interested in

The population, P(t), of China, in billions, can be approximated by1 P(t)=1.394(1.006)t, where t is the number of years since th

vitfil [10]

Answer:

At the start of 2014, the population was growing at 8.34 million people per year.

At the start of 2015, the population was growing at 8.39 million people per year.

Step-by-step explanation:

To find how fast was the population growing at the start of 2014 and at the start of 2015 we need to take the derivative of the function with respect to t.

The derivative shows by how much the function (the population, in this case) is changing when the variable you're deriving with respect to (time) increases one unit (one year).

We know that the population, P(t), of China, in billions, can be approximated by $P(t)=1.394(1.006)^t$

To find the derivative you need to:

$\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=\\\\\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\1.394\frac{d}{dt}\left(1.006^t\right)\\\\\mathrm{Apply\:the\:derivative\:exponent\:rule}:\quad \frac{d}{dx}\left(a^x\right)=a^x\ln \left(a\right)\\\\1.394\cdot \:1.006^t\ln \left(1.006\right)\\\\\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=(1.394\cdot \ln \left(1.006\right))\cdot 1.006^t$

To find the population growing at the start of 2014 we say t = 0

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(0)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^0\\P(0)' = 0.00833901 \:Billion/year$

To find the population growing at the start of 2015 we say t = 1

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(1)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^1\\P(1)' = 0.00838904 \:Billion/year$

To convert billion to million you multiple by 1000

$P(0)' = 0.00833901 \:Billion/year \cdot 1000 = 8.34 \:Million/year \\P(1)' = 0.00838904 \:Billion/year \cdot 1000 = 8.39 \:Million/year$

6 0

3 years ago

HELP PLEASE WILL PICK BRAINLEST IF I ANSWER CORRECTLY!<br> the bubble thats in igonore it!

vampirchik [111]

Answer:

4. (d, the last one)

5. (a, the first one)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

How do I factor out the coefficient of the variable -3/5k-3/10?

Helen [10]

Answer:

make all the numbers have the same denominator, then simply see what multiplies to equal both fractions. your answer should be -3/10(1/5k+1)

Step-by-step explanation:

7 0

3 years ago

What is the missing reason in step 5?

DENIUS [597]

Answer:

The Correct Answer On Edgen2020 Is

A) Linear pair postulate.

Good Luck!! :))

7 0

3 years ago

Read 2 more answers

Simplify.<br><br> (2m^3n^2)^5

pashok25 [27]

10m15n10 because you just multiply everything by 5

6 0

3 years ago