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34kurt
3 years ago
5

What is the product?

Mathematics
1 answer:
Sveta_85 [38]3 years ago
3 0

( - 6 {a}^{3} b + 2a {b}^{2} )(5 {a}^{2}  - 2a {b}^{2}  - b) \\  =  - 30 {a}^{5} b + 12 {a}^{4}  {b}^{3}  + 16 {a}^{3}  {b}^{2}  - 4 {a}^{2}  {b}^{4}  - 2a {b}^{3}

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How many whole numbers leave a remainder of 2 when divided into 56, and a remainder of 1 when divided into 28? a.) 0 b.) 2 c.) 3
meriva

56 would have a remainder of 2 using multiples of 3

56/3 = 18 remainder 2

56/6 = 9 remainder 2

56/9 = 6 remainder 2

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Now divide 28 by the above numbers to see which ones have 1 as a remainder:

28/3 = 9 remainder 1

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There are 3 numbers that will work.

Answer: c. 3

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