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3 years ago

Brian spends 3 5 of his wages on rent and 1 3 on food. If he makes £735 per week, how much money does he have left?

Mathematics

1 answer:

Margarita [4]3 years ago

3 0

Answer :

Brian has $49 left.

Step by step explanation :

Step 1 : Find how much money Brian spends on rent and food.

First question we should be asking is what is 3/5 of 735?

Let's find that.

$\frac{3}{5}$ * $\frac{735}{1}$

= $\frac{(3)(735)}{(5)(1)}$

= $\frac{2205}{5}$

= 441

We know Brian spends $441 on rent. Now we find how much he spends on food.

$\frac{1}{3} * \frac{735}{1}$

= $\frac{(1)(735)}{(3)(1)}$

= $\frac{735}{3}$

= 245

Brian spends $245 on food.

Step 2 : Add what he spends on rent and food together.

$441 + $245 = $686

Step 3 : To find out how much money Brian has left, we subtract $686 from $735.

$735 - $686 = $49

Conclusion : Brian has $49 left.

Hope this helps, please mark brainliest if possible. Have a nice day.

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Need to write steps and solve thanks

nalin [4]

Answer:

The coordinates of endpoint V is (7,-27)

Solution:

Given that the midpoint of line segment UV is (5,-11) And U is (3,5).

To find the coordinates of V.

The formula for mid-point of a line segment is as follows,

Midpoint of UV is $\frac{x_{1}+x_{2}}{2}$ , $\frac{y_{1}+y_{2}}{2}$

As per the formula, $\frac{x_{1}+x_{2}}{2}$ =5, $\frac{y_{1}+y_{2}}{2}$ =-11

Here $x_{1}=3; y_{1}=5$

Substituting the value of $x_{1}$ we get,

$\frac{3+x_{2}}{2}$ =5

$3+x_{2}=5\times2$

$x_{2}=10-3$

$x_{2}=7$

Substituting the value of $x_{2}$ we get,

$\frac{5+y_{2}}{2}$ =-11

$5+y_{2}=-11\times2$

$y_{2}=-22-5$

$y_{2}=-27$

So, the coordinates of V is (7,-27)

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3 years ago

If x = false and y = false, is the statement: not x or not y a) true b) false

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Answer:

false

Step-by-step explanation:

X is equal to Y

therefore,

X = Y

X= false

Y = false

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false = false

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Answer:

Step-by-step explanation:Answer Explanation

Correct answers:

$\left(241.42,\ 262.14\right)$

A 95% confidence interval for μ is (x¯−zα/2σn‾√,x¯+zα/2σn‾√). Here, α=0.05, σ=37, and n=49. Use Excel to calculate the 95% confidence interval.

1. Open Excel, enter the given data in column A, and find the sample mean, x¯, using the AVERAGE function. Thus, the sample mean, rounded to two decimal places, is x¯=251.78.

2. Click on any empty cell, enter =CONFIDENCE.NORM(0.05,37,49), and press ENTER.

3. The margin of error, rounded to two decimal places, is zα/2σn‾√≈10.36. The confidence interval for the population mean has a lower limit of 251.78−10.36=241.42 and an upper limit of 251.78+10.36=262.14.

Thus, the 95% confidence interval for μ is (241.42, 262.14).

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I hope this was helpful.

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3 years ago

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