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Vladimir79 [104]
3 years ago
6

B)Given 0º < x < 360° , solve for x in: 2 sin (2x - 30°) = √3.​

Mathematics
1 answer:
Rainbow [258]3 years ago
3 0

Answer:

180°

because x is the mid pf 0° and 360°

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What is -2.4x +3.8x-x<br>​
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The answer is .4x because -3.4x+3.8x
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Solve the inequality:
steposvetlana [31]

Answer:

x >_ 1

Step-by-step explanation:

Solving an inequality is a lot like solving an equation. Just pretend the inequality symbol is an equal sign!

(also i wont be using the _ or equal to symbol because I'm too lazy, so you'll get >_ or <_ for those, sorry)

8 + 4x >_ 12

-8             -8

4x >_ 4

/4       /4

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Which of these debts could possibly be forgiven under Chapter 7 bankruptcy? A. Credit Card Debt B. Child Support C. Alimony D. A
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4 0
4 years ago
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The second statement is the ____ of the first.
iren [92.7K]

Answer:

A. Converse

Step-by-step explanation:

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converse relation

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1. Inverse

2. Contrapositive inverse

3.converse

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7 0
3 years ago
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I need help solving this problem. <img src="https://tex.z-dn.net/?f=4x%20cos%20%5E%7B-1%7D%20%282x%2B4%29-%20%5Csqrt%7B3-3%20x%5
Gnesinka [82]
Given:
f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}

Using
\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}
we derive
\frac{d}{dx}4xcos^{-1}(2x+4)
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}

Similarly, using
\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}
we derive
\frac{d}{dx}(-\sqrt{3-3x^2})
=\frac{3x}{\sqrt{3-3x^2}}

Therefore, the derivative is
f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}
3 0
3 years ago
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