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3 years ago

Anybody help me please!!!!!!!!

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

7 0

Answer:

A reflection over the x-axis

Step-by-step explanation:

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12e^5 divided 3e^3 simplified

bonufazy [111]

Answer:

$4 {e}^{2}$

Step-by-step explanation:

$\frac{12 {e}^{5} }{3 {e}^{3} } \\ 12 \div 3 \times {e}^{5 - 3} \\ = 4 {e}^{2}$

hope this helps

brainliest appreciated

good luck! have a nice day!

6 0

3 years ago

there are 12 ducks and 15 gesse swimming in a pond. what is the ratio of gesse to total brids at the pond?

lana66690 [7]

Best Answer: 15 (number of geese) : 27 (total # of birds)<span>
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3 0

2 years ago

Read 2 more answers

Consider the line y = 3/8x + 3

Finger [1]

Answer:

Perpendicular line y = (- 8/3)x - 76/3.

Parallel line y = (3/8)x - 1

Step-by-step explanation:

y = 3/8

x + 3

1) Perpendicular line has negative reciprocal slope.

m = - 8/3

y = (- 8/3)x + b

Point (-8, - 4)

- 4 = (- 8/3)*(-8) + b

-4 - 64/3 = b

b = - 76/3

y = (- 8/3)x - 76/3

2) Parallel line has the same slope.

m = 3/8

y = (3/8)x + b

Point (-8, -4)

- 4 = (3/8)*(- 8) + b

- 4 + 3 = b

b = - 1

y = (3/8)x - 1

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%7B6m%7D%5E%7B3%20%7D%20%20n%20%7B%7D%5E%7B3%7D%20%20%5Ctimes%208m%20%7B%7D%5E%7B2%7D%20n%5

just olya [345]

Answer:

$48 {m}^{5} {n}^{6}$

Step-by-step explanation:

$6{m}^{3} {n}^{3} \times 8 {m}^{2} {n}^{3}$

$8 \times 6 = 48$

$6{m}^{3} {n}^{3} \times 8 {m}^{2} {n}^{3} = 48 {m}^{3 + 2} {n}^{3 + 3}$

Therefore

$48 {m}^{5} {n}^{6}$

5 0

2 years ago

Center: (10,-10)

vova2212 [387]

This is the standard form equation $\frac{(x - 10)^2}{100} + \frac{(y + 10)^2}{-100} = 1$

What is the ellipse?

The equation for an ellipse is typically written as x² a² + y² b² = 1. x² a² + y² b² = 1. An ellipse with its origin at the center is defined by this equation. The ellipse is stretched further in both the horizontal and vertical directions if a > b, a > b, and if b > a, b > a, respectively.

The standard form of the equation of an ellipse with center (h, k)and major axis parallel to the x-axis is:

$\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1$

where,

a > b

the length of the major axis is 2a

the coordinates of the vertices are (h±a,k)

the length of the minor axis is 2b

the coordinates of the co-vertices are (h,k±b)

the coordinates of the foci are (h±c,k),

where c² = a² − b².

so,

$\frac{(x - 10)^2}{100} + \frac{(y + 10)^2}{-100} = 1$

Hence, this is the standard form equation $\frac{(x - 10)^2}{100} + \frac{(y + 10)^2}{-100} = 1$ .

To learn more about ellipse, visit

brainly.com/question/16904744

#SPJ1

7 0

1 year ago