Hope this helps you.
If f(x) = x 2 + 1 and g(x) = 3x + 1, find [f(2)-g(1)] 2. 1 2 9
1 answer:
You might be interested in
Answer:
a =
Step-by-step explanation:
Given:
f(x) = log(x)
and,
f(kaa) = kf(a)
now applying the given function, we get
⇒ log(kaa) = k × log(a)
or
⇒ log(ka²) = k × log(a)
Now, we know the property of the log function that
log(AB) = log(A) + log(B)
and,
log(Aᵇ) = b × log(A)
Thus,
⇒ log(k) + log(a²) = k × log(a) (using log(AB) = log(A) + log(B) )
or
⇒ log(k) + 2log(a) = k × log(a) (using log(Aᵇ) = b × log(A) )
or
⇒ k × log(a) - 2log(a) = log(k)
or
⇒ log(a) × (k - 2) = log(k)
or
⇒ log(a) = (k - 2)⁻¹ × log(k)
or
⇒ log(a) = (using log(Aᵇ) = b × log(A) )
taking anti-log both sides
⇒ a =
Answer:
Therefore 80 ceperies will he need to sell this month.
Step-by-step explanation:
Average: Average is the ratio of sum of all numbers to the total number present in the data.
Given that Herbert has sold 99, 37, 86 and 73 copeirs in the last 4 months.
Let he need to sell x copeirs in this month.
According to the problem,
⇒ 99+37+86+73+x= 75×5
⇒295 + x= 375
⇒x = 375 - 295
⇒ x= 80
Therefore 80 ceperies will he need to sell this month.