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Arada [10]
3 years ago
9

A snail is moving along a path that is 4 meters long. The snail moves at an average rate of 3 3/10 inches per minute. Question 1

Part A Find the length of the path to the nearest inch. (Hint: 1 in.≈2.54 cm) Enter the correct answer in the box.
Mathematics
1 answer:
Troyanec [42]3 years ago
5 0

Answer: The length of the path = 157 inches { approx}

Step-by-step explanation:

Given: The length of the path = 4 meters

1 meter = 100 centimeters

So 4 meters = 400 centimeters

Also 1 in. ≈ 2.54 cm

\Rightarrow\ 1 cm = \dfrac{1}{2.54}\ in.

Now, \text{ 400 centimeters}=400\times\dfrac{1}{2.54}\text{ inches}

=157.480314961\approx 157  \ \ \ \ \ \text{ [Rounded to the nearest inch.]}

Hence, the length of the path = 157 inches { approx}

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If v varies directly as w, and v=24 when w= 8, find the equation that relates v and w
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3 years ago
Answer this question​
Stells [14]

Answer:

\huge\boxed{width=12cm}

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l-length\\w-width\\P-perimeter

The formula of perimeter of the rectangle:

P=2l+2w=2(l+w)

Substitute:

l=6w\\\\P=168cm

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3 0
3 years ago
Twenty seven pears are packed in bags of three. Five bags of pears are sold. How many pears are left
aliya0001 [1]

Answer:

Pears\ Left = 12

Step-by-step explanation:

Given

Pears = 27

Bags\ Sold = 5

Required

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First, we need to determine the number of bags for 27 pears;

Since they are packed in 3s

Bags = 27/3

Bags = 9

Hence:

9 bags were used for 27 pears;

After 5 bags were sold, we have:

Bags\ Left = 9 - 5

Bags\ Left = 4

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So:

Pears\ Left = 4 * 3

Pears\ Left = 12

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3 years ago
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