<span>Dayson has 1 m2 of wrapping paper, which is 10000 cm2:
1 m = 100 cm
1 m^2 = (100 cm)^2
</span>1 m^2 = 10000 cm^2
<span>The package has a surface area of cm2:
A = 2*(50*20) + </span>2*(50*18) + 2*(18*20)
A = <span>
<span>4520 cm^2
</span></span>The area of the package is less than the area of the wrapping paper (4520 cm^2 < 10000 cm^2<span>). So, Dayson cover the package with the wrapping paper.</span>
<span>Answer:
K = (1/2) mv² + (1/2) Iω², where m is the ball mass, I is the ball's moment of inertia (2/5)mr², and ω is the angular velocity of the ball. Because the ball rolls without slipping, it is easy to see that v=ωr, or r=v/ω. Then,
K = (1/2)mv² + (1/2)(2/5)mr²ω²
= (1/2)mv² + (1/5)mv²
= (7/10)mv²
Setting potential at the top equal to kinetic at the bottom,
mgh=(7/10)mv²
v=âš{(10/7)(gh)}
= [(10/7)(9.8)(0.51)]^(1/2) = 2.672m/s</span>
a=1 b= c=Step-by-step explanation:
Answer:
30 degrees
Step-by-step explanation:
The angles must add up to 180 degrees and the triangles have the same angles.
