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astraxan [27]
2 years ago
9

Dan is watching the birds in his backyard. Of the birds he watches, 9 of them, or 45%, are sparrows. How may birds are in his ba

ckyard?
Mathematics
2 answers:
Marat540 [252]2 years ago
8 0

Answer:

20 birds in the backyard.

Step-by-step explanation:

andrezito [222]2 years ago
6 0

Answer:

5

Step-by-step explanation:45 divided by 9 is 5

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$1,000, 5%, 2 years of simple interest paid to the nearest cent
yawa3891 [41]
Using the formula for simple interest
(1000 X 5 X 2)/100
the answer is $100 but to the nearest cent it is 10000cents
7 0
3 years ago
Simplify numbers with units 1.<br> ​
Vilka [71]

Answer:

1. 1 min : 2 min

2. 1 min : 4 min

3. 1 : 5

4. 1 : 2

5. 1 hr : 4 hrs

6. 7 p : 10 p

7. 5 : 2 : 3

8. 1 : 3

9. 3 : 5

Step-by-step explanation:

break it down to the lowest, which means to keep dividing it till it can't anymore.

hope that helps

3 0
3 years ago
Determine whether the vectors u and v are parallel, orthogonal, or neither.
kicyunya [14]

Answer:

B.) Orthogonal

Step-by-step explanation:

Two vectors u and v whose dot product is u·v=0 are said to be orthogonal

u = <6, -2>, v = <2, 6>

u·v = u1*v1 + u2*v2

          6*2 + -2 * 6

        =12 -12

         =0

4 0
3 years ago
Read 2 more answers
Consider the following region R and the vector field F. a. Compute the​ two-dimensional curl of the vector field. b. Evaluate bo
Shalnov [3]

Looks like we're given

\vec F(x,y)=\langle-x,-y\rangle

which in three dimensions could be expressed as

\vec F(x,y)=\langle-x,-y,0\rangle

and this has curl

\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle

which confirms the two-dimensional curl is 0.

It also looks like the region R is the disk x^2+y^2\le5. Green's theorem says the integral of \vec F along the boundary of R is equal to the integral of the two-dimensional curl of \vec F over the interior of R:

\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of R by

\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle

\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt

with 0\le t\le2\pi. Then

\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt

=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0

7 0
3 years ago
Please help me with this equation, add process too. Thanks
ICE Princess25 [194]

\qquad\qquad\huge\underline{\boxed{\sf Answer☂}}

Let's solve ~ ☂

\qquad \sf  \dashrightarrow \:  - 0.6(m + 1) = 3

\qquad \sf  \dashrightarrow \:  - (m + 1) = 3 \div 0.6

\qquad \sf  \dashrightarrow \:  - (m + 1) = 5

\qquad \sf  \dashrightarrow \:  - m  -  1= 5

\qquad \sf  \dashrightarrow \:  - m = 5 + 1

\qquad \sf  \dashrightarrow \:  - m =  6

\qquad \sf  \dashrightarrow \: m =  - 6

I hope it helps ~

6 0
2 years ago
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