ANSWER:
n = 1.05n divided by 105 times 100
OR
n = (the number of students at the END of the school year) divided by 105 times 100
WORKING OUT:
1.05n = 651 students
1n = 651/105 times 100 = ANSWER
Answer:
y = 2
x = 50
Step-by-step explanation:
We can first find y by doing 12y+5 = 18y-7 since vertical angles are always congruent.
We want to combine like terms so we subtract 12y from both sides (what you do on one side needs to be done to the other) and we get 5 = 6y-7 and now we add 7 to both sides to get 12 = 6y.
Like I said we did this because we combine like terms!!!
Now we want to isolate the y and we do this by dividing 6 from both sides which lets us get 2 = y
Now that we know what y is we can plug it into any of the equations using y.
I plugged it into the top right equation cause it was easier.
12(2)+5
24+5
29!
That angle is 29!
Now that we know that we can begin solving for x.
The equation that has x + 29 make 180 degrees because it is a straight line so we use this to solve for x!
3x+1+29=180 (We want to start combining like terms now)
3x+30=180(Subtract 30 from both sides)
3x=150 (Isolate the x by dividing 3 from both sides)
x=50!
We can prove this is right by inserting x into it's expression. That tells us the angle is 151. Now we add 151+151+29+29 and we get 360!
Answer:
165 crackers.
Step-by-step explanation:
33x5=165 crackers
100miles in 2hrs
650miles in x hrs
If you think of it 650/100 = 6.5
So the distance is 6.5 times
So the time is 6.5 times 2hrs
=13 hrs total
Answer:
Four unique planes
Step-by-step explanation:
Given that the points are non co-planar, triangular planes can be formed by the joining of three points
The points will therefore appear to be at the corners of a triangular pyramid or tetrahedron such that together the four points will form a three dimensional figure bounded by triangular planes
The number of triangular planes that can therefore be formed is given by the combination of four objects taking three at a time as follows;
₄C₃ = 4!/(3!×(4-3)! = 4
Which gives four possible unique planes.
