The area of a circle A equals either:
πr² or πd²/4
96 = πd²/4 => d = 11 inches
The diameter of the second circle equals :
11*1.5 = 16.5 inches
The area equals: π(16.5)²/4 = 214 square inches
Good luck
Answer:
x=1
Step-by-step explanation:
According to your typed question,
f(x)=2x-3
Let f(x)=y
y=2x-3
Now,
Interchanging the positions of x and y
x=2y-3
x+3=2y
x+3/2=y
f'(x)=x+3/2
Then,
f(x)=f'(x)
2x-3=x+3/2
2(2x-3)=x+3
4x-3=x+3
4x-x=3+3
3x=3
x=3/3
x=1
According to your image question,
f(x)=x/2x-3
f(x)=f'(x)
Now,
Let y=f(x)
y=x/2x-3
y(2x-3)=x
2xy-3=x
2xy-x=3
x(2y-1)=3
2y-1=3x
2y=3x+1
y=3x+1/2
f'(x)=3x+1/2
Then,
f(x)=f'(x)
x/2x-3=3x+1/2
2x=6xsq+2x-9x+3
2x=6xsq+7x+3
solve for x ok
Answer:
look at the attachment
Step-by-step explanation:
hope it helps!
Answer:
width = 3.5 m
length = 18 m
Step-by-step explanation:
area = length x width
x is the width then length = 2x + 11
x(2x + 11) = 63
2x^2 + 11x - 63 = 0
The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a
with a = 2
b = 11
c = -63
substitute in the formula
x = [-11 +/- √(11^2 - 4(2)(-63))]2(2)
x = [-11 +/- √(121 + 504)]/4
x = [-11 +/- √625]/4
x = (-11 +/- 25)/4
x1 = (-11 + 25)/4 = 14/4 = 3.5
x2 = (-11 - 25)/4 = -36/4 = -9
since width can't be a negative number, x is 3.5
length = 2x + 11 = 2(3.5) + 11 = 18
