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dalvyx [7]
3 years ago
9

Plz help stuck on the question

Mathematics
1 answer:
Gekata [30.6K]3 years ago
5 0
The length of the rectangle is n-3, ok, the width is 2

the area of a rectangle is just length * width

\bf A=(n-3)(2)\implies \boxed{A=2n-6}
\\\\\\
\textit{to make some equivalent, let's use our good friend Mr 1}
\\\\\\
\textit{recall that }\cfrac{whatever}{whatever}=1\qquad \qquad \cfrac{same}{same}=1
\\\\\\
\cfrac{55}{55}\cdot 2n-6\implies \cfrac{55(2n-6)}{55}\implies \cfrac{110n-330}{55}
\\\\\\
or
\\\\\\
\cfrac{xyz}{xyz}\cdot 2n-6\implies \cfrac{xyz(2n-6)}{xyz}\implies \cfrac{2nxyz-6xyz}{xyz}

so, if you simplify either of those, you'd end up with 2n-6.

because same/same = 1, and 1 * anything, is just anything itself.
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Step-by-step explanation:

The equation that we have to solve in this problem is:

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The first step to do is to rewrite the mixed fractions as improper fractions. We have:

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