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dalvyx [7]
3 years ago
9

Plz help stuck on the question

Mathematics
1 answer:
Gekata [30.6K]3 years ago
5 0
The length of the rectangle is n-3, ok, the width is 2

the area of a rectangle is just length * width

\bf A=(n-3)(2)\implies \boxed{A=2n-6}
\\\\\\
\textit{to make some equivalent, let's use our good friend Mr 1}
\\\\\\
\textit{recall that }\cfrac{whatever}{whatever}=1\qquad \qquad \cfrac{same}{same}=1
\\\\\\
\cfrac{55}{55}\cdot 2n-6\implies \cfrac{55(2n-6)}{55}\implies \cfrac{110n-330}{55}
\\\\\\
or
\\\\\\
\cfrac{xyz}{xyz}\cdot 2n-6\implies \cfrac{xyz(2n-6)}{xyz}\implies \cfrac{2nxyz-6xyz}{xyz}

so, if you simplify either of those, you'd end up with 2n-6.

because same/same = 1, and 1 * anything, is just anything itself.
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The best way to solve this equation is to simplify it. So first you’ll distribute the -2 on the left side. This will give you the equation -2t+8=10-2t. Now you bring t to one side by adding 2t to both sides. You will find that t cancels out and you are left with 8=10. Since this statement isn’t true there are no solutions to this equation.
3 0
3 years ago
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Define a variable, write an equation, and solve.
allochka39001 [22]

Answer:

  • c(m) = 39.95 +0.35m
  • 85 minutes over 500

Step-by-step explanation:

Let m represent the number of minutes used over 500. Then the cost of the cell phone plan is ...

  c(m) = 39.95 +0.35m

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For a cost of 69.70, the number of excess minutes can be found by solving ...

  69.70 = 39.95 +0.35m

  29.75 = 0.35m . . . . . . . . . subtract 39.95

  29.75/0.35 = m = 85 . . . . divide by the coefficient of m

The number of minutes of usage over 500 is 85.

3 0
3 years ago
A cylindrical tank is filled with 66.85 mm3 of fuel. The area of the base of the cylinder is 15 mm2. What is the height of the f
Rashid [163]
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3 0
4 years ago
The Versatech Corporation has decided to produce three new products. Five branch plants now have excess production capacity. The
RSB [31]

Answer: provided in the explanation segment

Step-by-step explanation:

here i will give a step by step analysis of the question;

A: Optimization Formulation

given Xij = X no. of units of product i manufactured in Plant j, where i = 1,2,3 and J = 1,2,3,4,5

Objective function: Minimize manufacturing cost (Z)

Z = 31 X11 + 29 X12 + 32X13 + 28X14 + 29 X15 + 45 X21 + 41 X22 + 46X23 + 42X24 + 43 X25 + 38 X31 + 35 X32 + 40X33

s.t

X11 + X12 + X13 + X14 + X15 = 600

X21 + X22 + X23 + X24 + X25 = 1000

X31 + X32 + X33 = 800

X11 + X21 + X31 <= 400

X12 + X22 + X32 <= 600

X13 + X23 + X33 <= 400

X14 + X24 ​​​​​​ <= 600

X15 + X25 <= 1000

Xij >= 0 for all i,j

B:

Yes, we can formulate this problem as a transportation problem because in transportation problem we need to match the supply of source to demand of destination. Here we can assume that the supply of source is nothing but the manufacturing capability of plant and demand of destination is similar to the demand of products.

cheers i hope this helps!!

3 0
4 years ago
Which exponential function/geometric sequence matches the graph?
muminat
The answer is D for sure :) y = 2^(1) = 
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