The best way to solve this equation is to simplify it. So first you’ll distribute the -2 on the left side. This will give you the equation -2t+8=10-2t. Now you bring t to one side by adding 2t to both sides. You will find that t cancels out and you are left with 8=10. Since this statement isn’t true there are no solutions to this equation.
Answer:
- c(m) = 39.95 +0.35m
- 85 minutes over 500
Step-by-step explanation:
Let m represent the number of minutes used over 500. Then the cost of the cell phone plan is ...
c(m) = 39.95 +0.35m
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For a cost of 69.70, the number of excess minutes can be found by solving ...
69.70 = 39.95 +0.35m
29.75 = 0.35m . . . . . . . . . subtract 39.95
29.75/0.35 = m = 85 . . . . divide by the coefficient of m
The number of minutes of usage over 500 is 85.
Volume = (Area of the base)x(Height)
66.85 = 15(H)
66.85/15 = H
H = 4.4567
The height is 4.4567mm.
Answer: provided in the explanation segment
Step-by-step explanation:
here i will give a step by step analysis of the question;
A: Optimization Formulation
given Xij = X no. of units of product i manufactured in Plant j, where i = 1,2,3 and J = 1,2,3,4,5
Objective function: Minimize manufacturing cost (Z)
Z = 31 X11 + 29 X12 + 32X13 + 28X14 + 29 X15 + 45 X21 + 41 X22 + 46X23 + 42X24 + 43 X25 + 38 X31 + 35 X32 + 40X33
s.t
X11 + X12 + X13 + X14 + X15 = 600
X21 + X22 + X23 + X24 + X25 = 1000
X31 + X32 + X33 = 800
X11 + X21 + X31 <= 400
X12 + X22 + X32 <= 600
X13 + X23 + X33 <= 400
X14 + X24 <= 600
X15 + X25 <= 1000
Xij >= 0 for all i,j
B:
Yes, we can formulate this problem as a transportation problem because in transportation problem we need to match the supply of source to demand of destination. Here we can assume that the supply of source is nothing but the manufacturing capability of plant and demand of destination is similar to the demand of products.
cheers i hope this helps!!
The answer is D for sure :) y = 2^(1) =
y = 2 which is a plot on the graph.