Question

Of their first 18 games of the season, the

Answer 1

Answer:

77.78%

Step-by-step explanation:

Let us start this problem by finding the fraction of games the Cubs won in that season. In the numerator, we should have the number of games they won. In the denominator, we will have the total number of games they played.

Let us find the number of games the Cubs won. We know they played a total of 18 games and lost 4 games. Therefore, the remainder must be the games they won -- we subtract the two values:

$18-4=14$ games won

As mentioned before, we also know the total number of games they played, given to us -- 18 games. We can now form our fraction and simplify it.

$\frac{14}{18} =\\\frac{7}{9}$games won

To find the percent, let us find the decimal value first. After calculation, $\frac{7}{9}$ = 0.7778

To convert this value into a percentage, we simply shift the decimal point to digits to the right. We now have

77.78%

Therefore, the Cubs won 77.78% of their games.

I hope this helps! Let me know if you have any questions :)