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uysha [10]
3 years ago
6

The picture shows the graphs of the functions expressed by a formula of the following type: y = kx + b.

Mathematics
2 answers:
ollegr [7]3 years ago
7 0

Answer:

line 1: y= 1x+ 2

line 2: y= -1x-0.5

(usually 1 is omitted but I added for clarity)

Step-by-step explanation:

slope (x)= yfinal-yintial/xfinal-xinitial

b= where line intersects y axis

line 1:  (-1,0), (0.5,1.5)

(1.5-0)/(0.5-(-1))

(1.5)/(1.5)

slope= 1x

y=x+ 2

line 2: (-0.5,0), (0.5,-1)

(-1-0)/(0.5-(-0.5))

(-1)/(1)

slope= -1x

y=-x-0.5

jeka943 years ago
4 0
First: k is 1, b is 1.
second: k is -1, b is -0.5
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Suppose a random sample of 100 observations from a binomial population gives a value of pˆ = .63 and you wish to test the null h
irakobra [83]

Answer:

We conclude that the population proportion is equal to 0.70.

Step-by-step explanation:

We are given that a random sample of 100 observations from a binomial population gives a value of pˆ = 0.63 and you wish to test the null hypothesis that the population parameter p is equal to 0.70 against the alternative hypothesis that p is less than 0.70.

Let p = <u><em>population proportion.</em></u>

(1) The intuition tells us that the population parameter p may be less than 0.70 as the sample proportion comes out to be less than 0.70 and also the sample is large enough.

(2) So, Null Hypothesis, H_0 : p = 0.70      {means that the population proportion is equal to 0.70}

Alternate Hypothesis, H_A : p < 0.70      {means that the population proportion is less than 0.70}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                           T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion = 0.63

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So, <u><em>the test statistics</em></u>  =  \frac{0.63-0.70}{\sqrt{\frac{0.70(1-0.70)}{100} } }

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The value of z-test statistics is -1.528.

<u>Now at 0.05 level of significance, the z table gives a critical value of -1.645 for the left-tailed test.</u>

Since our test statistics is more than the critical value of z as -1.528 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the population proportion is equal to 0.70.

(c) The observed level of significance in part B is 0.05 on the basis of which we find our critical value of z.

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