We know the coordinates of two points on the line—(-2,0) and (0,4)—which we can use to find the slope.
Slope = Δy/Δx = (4-0)/(0-(-2)) = 2.
And as we conveniently just noted, when x = 0, y = 4. So, the slope-intercept form of the equation of this line is y = 2x + 4.
The volume of a box is the length x with x height. Because it is a cube all the sides are the same size, and it’s has three dimensions. That means you can calculate the length of one side by picking the root^3 (I don’t know what it is in English it is a square root with a 3 in the upper left corner) of 512. That gives you 8, so the sides are 8 inches Kong’s
Answer:
17
Step-by-step explanation:
3 + 7 * 6 / 3
PEMDAS says we multiply and add before adding and subtracting so we multiply first (going from left to right)
3 + 42 / 3
Then we divide
3 + 14 = 17
Answer:
W=7 and L=11
Step-by-step explanation:
We have two unknowns so we must create two equations.
First the problem states that length of a rectangle is 10 yd less than three times the width so: L= 3w-10
Next we are given the area so: L X W = 77
Then solve for the variable algebraically. It is just a system of equations.
3W^2 - 10W - 77 = 0
(3W + 11)(W - 7) = 0
W = -11/3 and/or W=7
Discard the negative solution as the width of the rectangle cannot be less then 0.
So W=7
Plug that into the first equation.
3(7)-10= 11 so L=11
