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sattari [20]
4 years ago
7

Find the value of the discriminant and determine the number of real-number solutions for this quadratic equation. y^2+3y-4=0

Mathematics
1 answer:
Step2247 [10]4 years ago
6 0
I hope this helps you



1.y^2+3y-4 =0


a=1


b=3


c= -4


disctirminant=b^2-4ac



disctirminant=3^2-4.1.(-4)


disctirminant=9+16


disctirminant=25
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