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3 years ago

An athlete ran 10 times around the circular track shown below. Approximately how many meters did the athlete run?

Mathematics

1 answer:

Anon25 [30]3 years ago

5 0

Answer:

Step-by-step explanation:

Since the picture isn't given. I have no idea what the radius or diameter is and as such, have no definite answer for you.

However, from the question, if he's to run round the circular track once, then he must have run a total of

2πr meters, with r being the radius.

Now, the question says that he ran round the track 10 times, this means that whatever value we get there, for 1 trial, we multiply it by 10, to get the value for 10 trials. Essentially,

10 * 2πr

The value gotten is the needed answer. All you have to do is substitute r for the value you have in your diagram. We already know that π is 3.142

You might be interested in

A rectangular field is nine times as long as it is wide. If the perimeter of the field is 1700 feet, what

Leokris [45]

Answer:

I. L = 10.35 feet

II. W = 93.15 feet.

Step-by-step explanation:

Let the length of the rectangle be L.

Let the width of the rectangle be W.

Given the following data;

Perimeter of rectangular field = 1700 feet

Translating the word problem into an algebraic expression, we have;

W = 9L

Mathematically, the formula for the perimeter of a rectangle is;

P = 2(L + W)

A. To write an equation;

X = P = 2(L + W)

B. To find the dimensions of the field;

207 = 2(L + 9L)

207 = 2L + 18L

207 = 20L

L = 207/20

L = 10.35 feet

To find the weight;

W = 9L

W = 9 * 10.35

W = 93.15 feet.

Therefore, the width of the field is

93.15 feet and the length of the field is

10.35 feet.

6 0

3 years ago

Plz answer my question it is urgent..!!

oee [108]

Answer:

In the step-by-step explanation!

Step-by-step explanation:

Not sure if it is too late but here:

1.)

$\frac{1}{\alpha}+\frac{1}{\beta} \\\frac{\beta}{\alpha \beta } +\frac{\alpha}{\alpha \beta } \\\frac{\alpha +\beta }{\alpha \beta }$

2.)

$\frac{1 }{\alpha } *\frac{1}{\beta} = \frac{1*1}{\alpha*\beta} =\frac{1}{\alpha \beta}$

3.)

$\frac{1}{\alpha}-\frac{1}{\beta}\\ \frac{\beta}{\alpha \beta } -\frac{\alpha }{\alpha \beta } \\\frac{\beta -\alpha }{\alpha \beta }$

Hopes this help! Please give me Brainliest!

6 0

3 years ago

What is 2160 minus 1600 long way

lilavasa [31]

Hey there, Lets solve this problem together.

The First step is to line up the numbers.

$= 2160

- 1600$

$\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}$

We calculate $0-0$ the result of which is $0$ 

We calculate $6-0$ the result of which is $6$ .

Since we get a negative number in the next column, we must take 1 from the next column and carry it over to this column. Now the number will be changed to 10.

We calculate $10+1-6$ , and the result is $5$ .

We calculate $2-1-1$ the result of which is $0$ .

Therefore,

$2160 - 1600 = 0560$

8 0

3 years ago

Find the volume of this sphere. Use 3 for TT. V [?]in3 V = Tr3 8 in

frutty [35]

Answer:

The volume of the sphere is 2048 in³.

Step-by-step explanation:

The volume of a sphere is given by:

$V = \frac{4}{3}\pi r^{3}$

Where:

r: is the radius = 8 in

Having the radius and by using 3 for π, the volume is:

$V = \frac{4}{3}*3 (8 in)^{3} = 2048 in^{3}$

Therefore, the volume of the sphere is 2048 in³.

I hope it helps you!

4 0

3 years ago

You have a choice between 2 jobs, one pays $8.25/hr but requires you to spend $20 to get a uniform. The other pays $7.50/hr. At

Veronika [31]

Step-by-step explanation + Answer:

x = 1st job

y = 2nd job

x + y = 22......x = 22 - y

7x + 8.25y = 171.50

7(22 - y ) + 8.25y = 171.50

154 - 7y + 8.25y = 171.50

-7y + 8.25y = 171.50 - 154

1.25y = 17.50

y = 17.50 / 1.25

y = 14 <== 14 hrs at the 8.25 per hr job

x + y = 22

x + 14 = 22

x = 22 - 14

x = 8 <=== 8 hrs at the 7 per hr job

5 0

2 years ago