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3 years ago

12

The length of a rectangle is one more than four times it's width. if the perimeter of the rectangle is 62 m find the dimensions

of the rectangle

1 answer:

mr_godi [17]3 years ago

5 0

L=1+4W

2L+2W=62
2(1+4W)+2W=62
2+8W+2W=62
10W=60
W=6
L=25

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Add and Subtract Rational Expressions with a Common Denominator

Sladkaya [172]

Answer:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}$

Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}$

Operating on the numerators:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}$

Removing parentheses:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}$

Simplifying:

$\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}$

The expression cannot be further simplified.

7 0

2 years ago

If jim had 8 apples and you took 5 away and gave him two back how many apples do you have?

max2010maxim [7]

5 apples is the correct answer:)

8 0

2 years ago

If you use the addition property of equality , what number would you add to both sides of the equal sign to isolate the variable

kkurt [141]

Answer:

The answer is " $\frac{26}{7}$ "

Step-by-step explanation:

The whole question can be found in the file attached.

$\to x + \frac{5}{7} = \frac{31}{7}\\\\$

Subtracting the $\frac{5}{7}$ from both sides of the equations:

$\to x +\frac{5}{7} - \frac{5}{7} = \frac{31}{7} - \frac{5}{7} \\\\$

$= \frac{31-5}{7} \\\\= \frac{26}{7} \\\\$

5 0

3 years ago

Josh is hiking Glacier National Park. He has now hiked a total of 17 \text{ km}17 km17, start text, space, k, m, end text and is

EastWind [94]

Answer:

The equation to determine the total length in kilometers is $\frac{h}{2} =(17+2)$

The total length in kilometers of Josh’s hike is 38 km.

Step-by-step explanation:

Given:

Let the total length in kilometers of Josh’s hike be h.

Now Given that He has now hiked a total of 17 km and is 2 km short of being 1/2 of the way done with his hike.

It means that to reach half of the length of total length Josh needs 2 more km to add in his hiking which is done which is of 17 km.

Framing the above sentence in equation form we get;

$\frac{h}{2}=(17+2)$

Hence, The equation to determine the total length in kilometers is $\frac{h}{2} =(17+2)$

Now Solving the above equation we get;

First we will multiply 2 on both side using Multiplication property we get;

$2\times \frac{h}{2}= 2\times(17+2)\\\\h =2\times 19 =38 \ km$

Hence, The total length in kilometers of Josh’s hike is 38 km.

4 0

3 years ago

Read 2 more answers

Which equation is true when the value of x is -12

Sophie [7]

Answer:

Which equation is true when the value of x is -12 HERE YOU GO!!

Step-by-step explanation:

tricky ... let's see ...

I notice that if we subtract xy from both sides we get

7x + xy - xy = xy - xy + 21

then

7x = 21

and

x = 21/7 = 3

so there is only one value of x that satisfies the equation

x = 3

Going back to the original equation we see that any value of y will satisfy the original equation

we can see this by rearranging things:

7x + xy - xy = 21

here, I have performed the subtraction of xy on the right side as above, but have left the left side undone

(so we don't lose the presence of y)

Note that the above can also be written as

7x + (x - x)y = 21

or

7x + 0y =21

now, since anything times zero equals zero,

y may be any number.

Let's summarize:

1) x = 3

2) y = anything

looking back at the original question;

1) the equation is true for all ordered pairs

FALSE (only one x works, not all x)

2) there are no x and y pairs for which the equation is true.

FALSE (x=3, y=anything) makes it true, i.e. (3,1)

3) For each value of x, there is one and only one value of y that makes the equation true,

FALSE for each value of x, for the one value of x, x=3, y can be any number, which is an infinite number, not one

4) for each value of y, there is one and only on value of x that makes the equation true.

TRUE!! for all the infinite values of y you may pick, there is one and only one x you may pick, x = 3

ANSWER: STATEMENT 4 is CORRECT (TRUE)

3 0

3 years ago