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3 years ago

Just question 4 please. I NEED TO SHOW MY WORK AS TO HOW I GOT THE ANSWER!!!! Stuck someone please help?!!

Mathematics

1 answer:

Galina-37 [17]3 years ago

3 0

Well first you wanna see how many pints are in 3 quarts, which is 6 because there are 2 pints in a quart.

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What is the measure of DA? 15 90 105 165

seraphim [82]

Answer:

D. 165

Step-by-step explanation:

if A+n=180

75+90+n=180

165+n=180

n=180-165

n=15

A+n=180

A+15=180

A=180-15

A=165 (D)

3 0

2 years ago

Which equation represents the line that passes through (-6, 7) and (-3, 6)

Tju [1.3M]

Plug the given x and y values (x, y) into the equations and solve
It look like the second equation is the answer.
$6 = - \frac{1}{3} ( - 3) + 5 \\ 6 = 1 + 5 \\ true$

4 0

3 years ago

Read 2 more answers

40 points plz help if u can Which function has no Zeroes? Select all that apply.

Damm [24]

<h3>2 Answers: Choice C and choice D</h3>

y = csc(x) and y = sec(x)

==========================================================

Explanation:

The term "zeroes" in this case is the same as "roots" and "x intercepts". Any root is of the form (k, 0), where k is some real number. A root always occurs when y = 0.

Use GeoGebra, Desmos, or any graphing tool you prefer. If you graphed y = cos(x), you'll see that the curve crosses the x axis infinitely many times. Therefore, it has infinitely many roots. We can cross choice A off the list.

The same applies to...

y = cot(x)
y = sin(x)
y = tan(x)

So we can rule out choices B, E and F.

Only choice C and D have graphs that do not have any x intercepts at all.

------------

If you're curious why csc doesn't have any roots, consider the fact that

csc(x) = 1/sin(x)

and ask yourself "when is that fraction equal to zero?". The answer is "never" because the numerator is always 1, and the denominator cannot be zero. If the denominator were zero, then we'd have a division by zero error. So that's why csc(x) can't ever be zero. The same applies to sec(x) as well.

sec(x) = 1/cos(x)

7 0

2 years ago

1) Find the product: 6 x 1/3= * O 61/3 O 6/18 6/3 01/18

Kamila [148]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Use synthetic division to find the quotient and remainder. Express your answer as a polynomial.

OLEGan [10]

1. 2x³ - 11x² + 13x - 21 ÷ x - 3

x - 3 = 0 ⇒ x = 3

3 | 2 -11 13 -21

| ↓ 6 -15 -6

2 -5 -2 -27

1. Answer: 2x² - 5x - 2 - $\frac{27}{x - 3}$

*************************************************************

2. 3x³ + 7x² - 13x + 10 ÷ x + 2

x + 2 = 0 ⇒ x = -2

-2 | 3 7 -13 10

| ↓ -6 -2 30

3 1 -15 40

2. Answer: 3x² + x - 15 + $\frac{40}{x + 2}$

3. 2x³ + 13x² - 21x + 9 ÷ x - 1

x - 1 = 0 ⇒ x = 1

1 | 2 13 -21 9

| ↓ 2 15 -6

2 15 -6 3

3. Answer: 2x² + 15x - 6 + $\frac{3}{x - 1}$

4. 7x³ + 0x² - 8x + 16 ÷ x - 2

x - 2 = 0 ⇒ x = 2

2 | 7 0 -8 16

| ↓ 14 28 40

7 14 20 56

4. Answer: 7x² + 14x + 20 + $\frac{56}{x - 2}$

5. 8x⁴ - 14x³ - 71x² - 10x + 24 ÷ x - 4

x - 4 = 0 ⇒ x = 4

4 | 8 -14 -71 -10 24

| ↓ 32 72 4 -24

8 18 1 -6 0

5. Answer: 8x³ + 18x² + x - 6

8 0

3 years ago