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3 years ago

How do you solve 1/4x4/7=

2 answers:

8 0

If you would like to solve 1/4 * 4/7, you can do this using the following steps:

1/4 * 4/7 = (1 * 4) / (4 * 7) = 4/28 = 1/7

The correct result would be 1/7.

sergey [27]3 years ago

4 0

Answer:

4/28

1/7

Step-by-step explanation:

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I NEED HELP FAST ILL GIVE BRAINLIEST IF CORRECT!

klio [65]

Answer:

$1548ft$

Step-by-step explanation:

$V=lwh$

$V=(10)(3)(6)=180$

$V=(19)(12)(6)=1368$

$V$ $=180+1368=1548$

plz mark me brainliest. :)

7 0

3 years ago

5 5 I think of a number, treble it then add on 3, the result is equal to 6. Find the value of the original number I thought of.

Licemer1 [7]

Let the number be x

If 3 is added to tripple the number then the result is 6

$\\ \sf\longmapsto 3x+3=6$

$\\ \sf\longmapsto 3x=6-3$

$\\ \sf\longmapsto 3x=3$

$\\ \sf\longmapsto x=1$

8 0

2 years ago

Read 2 more answers

Pythagorean theorem (picture provided)

e-lub [12.9K]

The answer is of option D.

Hope this will help u...:)

8 0

3 years ago

Read 2 more answers

1.36 km is how many cm

Taya2010 [7]

Answer:

136000 cm

Step-by-step explanation:

I think it's helps you

5 0

3 years ago

Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form

Alex787 [66]

Answer:

$y=-\frac{2}{5}x-\frac{1}{5}$

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

m is the slope

b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

$m = -\frac{2}{5}$

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

$y=-\frac{2}{5}x + b$

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-3,1). When x of the line is -3, y of the line must be 1.
(2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: $y=-\frac{2}{5}x + b$ . $b$ is what we want, the - $-\frac{2}{5}$ is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

(-3,1). y = mx + b or $1=-\frac{2}{5} * -3 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(-3)$ . $b = -\frac{1}{5}$ .
(2,-1). y = mx + b or $-1=-\frac{2}{5} * 2 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(2)$ . $b = -\frac{1}{5}$ .

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points (-3,1) and (2,-1) is $y=-\frac{2}{5}x-\frac{1}{5}$

8 0

3 years ago