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Virty [35]
3 years ago
7

How do you solve 1/4x4/7=

Mathematics
2 answers:
Sveta_85 [38]3 years ago
8 0
If you would like to solve 1/4 * 4/7, you can do this using the following steps:

<span>1/4 * 4/7 = (1 * 4) / (4 * 7) = 4/28 = 1/7
</span>
The correct result would be 1/7.
sergey [27]3 years ago
4 0

Answer:

4/28

1/7

Step-by-step explanation:

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Answer:

1548ft

Step-by-step explanation:

V=lwh

V=(10)(3)(6)=180

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V=180+1368=1548

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5 5 I think of a number, treble it then add on 3, the result is equal to 6. Find the value of the original number I thought of.​
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Let the number be x

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\\ \sf\longmapsto 3x+3=6

\\ \sf\longmapsto 3x=6-3

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Step-by-step explanation:

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3 years ago
Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

  • m is the slope
  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

8 0
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