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Trava [24]
3 years ago
8

A quadrilateral must be a parallelogram if two the opposite sides are 1. Congruent only 2. Parallel only 3. Congruent and parall

el 4 parallel and the other two sides are congruent
Mathematics
1 answer:
Kobotan [32]3 years ago
7 0

Answer:

what’s the question

Step-by-step explanation:

1. Opposite Sides Theorem Converse: If both pairs of opposite sides of a quadrilateral are congruent, then the figure is a parallelogram. 2. Opposite Angles Theorem Converse: If both pairs of opposite angles of a quadrilateral are congruent, then the figure is a parallelogram.

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12-(4x2)=(12-4)x(12-2)=
faust18 [17]

Answer:

The awnser is Incorrect

Step-by-step explanation:

So do the Parentheses first (4x2)=8

12-4=8

12-2=10

Now do your multiplcation 8x10=80

Subtract 12-8=4

So the awnser is incorrect

6 0
3 years ago
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Solve for x in x²+8x+15=0 in factorisation method ​
Genrish500 [490]

Answer: x=-5, -3

Step-by-step explanation:

x^2 +8x+15=0\\\\(x+5)(x+3)=0\\\\x=-5, -3

7 0
2 years ago
Solve for W.<br><br> 4w-4+2(5w+8)=-2(w+3)<br><br> Simplify your answer as much as possible.
gayaneshka [121]

Answer:

w = -\frac{9}{8}

Step-by-step explanation:

The question is  4w-4+2(5w+8)=-2(w+3)

We can first use distributive property to simplify, the distributive property is  a(b+c)=ab+ac

Thus we have:

4w-4+2(5w+8)=-2(w+3)\\4w-4+10w+16=-2w-6

<em>Now we combine like terms and simplify to get the final answer for w</em><em>.</em>

4w-4+10w+16=-2w-6\\14w+12=-2w-6\\14w+2w=-6-12\\16w=-18\\w=\frac{-18}{16}\\w=-\frac{9}{8}

Thus, w = -\frac{9}{8}

8 0
3 years ago
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Evaluate 6j+23+kl−3, when j=3, k=7, and l=33.
madreJ [45]

The answer is 269. Hope this helped!! Could I possibly get brainliest!? :)


8 0
3 years ago
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Graph the image of this figure after a dilation with a scale factor of 2 centered at (2, 2) .
Fofino [41]

Answer:

The points of the dilated figure would be at (-2, 10), (2, 6), and (-8, 4); an image of the figure is attached.

Step-by-step explanation:

First we translate the center of dilation and figure so the origin becomes the center of dilation.

Since the point (2, 2) is our center of dilation, we must translate it left 2 and down 2 to make the origin the center; this means we map every point

(x, y)→(x-2, y-2)

The scale factor of 2 means that each point will be multiplied by 2; this gives us the rule

(x, y)→(2x-4, 2y-4)

Lastly we will translate the figure right 2 and up 2 to move it back to its original position; this gives us the rule

(x,y)→(2x-4+2, 2y-4+2) = (2x-2, 2y-2)

The first point in the original figure, at the top, is (0, 6).  Applying the transformation gives us

(0, 6)→(2*0-2, 2*6-2) = (0-2, 12-2) = (-2, 10)

The point on the right of the pre-image is (2, 4).  Applying the transformation rule gives us

(2, 4)→(2*2-2, 2*4-2) = (4-2, 8-2) = (2, 6)

The point on the left of the pre-image is at (-3, 3).  Applying the transformation rule, we have

(-3, 3)→(-3*2-2, 3*2-2) = (-6-2, 6-2) = (-8, 4)

7 0
3 years ago
Read 2 more answers
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