Question

Adrienne invested a total of $2900.00 in two simple-interest money market accounts. Account A paid 3% annual interest and account B paid 5% annual interest. The total amount of interest she earned after one year was $133.00. If a represents the amount invested in dollars in account A and b represents the amount invested in dollars in account B, the system of equations a + b = 2900.00 0.03a + 0.05b = 133.00 can be used to represent this situation. How much did Adrienne invest in each account? Adrienne invested $ in account A and $ in account B.

Answer 1

Solving the system of equations, it is found that Adrienne invested $1,366.67 in account A and $1,533.33 in account B.

System of equations:

The variables are:

• Variable A: Amount invested in account A.

• Variable B: Amount invested in account B.

The equations are:

$a + b = 2900$

$0.03a + 0.05b = 133$

From the first equation:

$a = 2900 - b$

Replacing on the second:

$0.03a + 0.05b = 133$

$0.03(2900 - b) + 0.05b = 133$

$0.03b = 46$

$b = \frac{46}{0.03}$

$b = 1533.33$

Then, on the first equation:

$a = 2900 - b = 2900 - 1533.33 = 1366.67$

Hence, Adrienne invested $1,366.67 in account A and $1,533.33 in account B.

To learn more about system of equations, you can take a look at brainly.com/question/14183076