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yulyashka [42]
3 years ago
14

Plz help ill give you brainlist

Mathematics
2 answers:
Natali5045456 [20]3 years ago
7 0
H= # hours rented

EQUATION:
$13.25>$1.75h + $8 fee

subtract 8 from both sides

5.25>1.75h
divide both sides by 1.75

3>h

He can rent the bike for 3 hours and not spend more than $13.25

Hope this helps!  :)

Ksenya-84 [330]3 years ago
5 0
Standard linear equation:
y=mx+b

Initial cost=initial value = b = 8  (Q did not say $8 is for any rental time).
additional cost per hour = m = 1.75

Equation becomes
y=1.75x+8

If the maximum charge is y=13.25, then we can solve for x, the maximum number of hours to be rented,

13.25=1.75x+8
Subtract 8 from each side
13.25-8=1.75x
5.25=1.75x
divide by 1.75
5.25/1.75=x
x=3

Connor can rent the bike for at most 3 hours.

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Step-by-step explanation:

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X^2+4x+4
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What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)
zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C

Arc Length Formula [Parametric]:                                                                         \displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.

Interval [0, π]

<u>Step 2: Find Arc Length</u>

  1. [Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]:         \displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.
  2. Substitute in variables [Arc Length Formula - Parametric]:                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx
  3. [Integrand] Simplify:                                                                                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx
  4. [Integral] Evaluate:                                                                                         \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0
3 years ago
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