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tekilochka [14]
3 years ago
8

8x=4x-2 solve for x please

Mathematics
2 answers:
julia-pushkina [17]3 years ago
5 0

Answer:

x=-1/2

Step-by-step explanation:

Subtract 4x from each side

8x-4x=4x-4x-2

Simplify

4x=-2

Divide each side by 4

4x/4=-2/4

Simplify

x=-1/2

Alexus [3.1K]3 years ago
4 0

X=-0.5

Move 4x to another side and you will get it.

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The perimeter of a square in which A=169cm square root 2?
sergey [27]
I'm guessing you mean:
A = 169 \sqrt{2}

If not, correct me. 

So, then the perimeter of a square is just 4*A, which in this case would be:
4(169 \sqrt{2}) = 676 \sqrt{2}

And that would be your answer: 676 \sqrt{2} units²
7 0
3 years ago
Jamal Buys a lunch special for $9.50And a dessert for $3.50. He wants to leave a tip that is about 15% of the bill. He estimates
sergey [27]

Answer:

  His estimate is somewhat low.

Step-by-step explanation:

The total bill is $9.50 +3.50 = $13.00. The estimated tip is 15% of $10, so Jamal needs to add 15% of $3, or $0.45, to his estimate to leave a tip equal to 15% of the bill.

The tip Jamal has calculated is about 11.5% of the bill. (1.50/13.00 ≈ 0.1154)

The tip Jamal wants to leave is $1.95. (0.15·13.00 = 1.95)

3 0
3 years ago
Eliminate the parameter and obtain the standard form of the rectangular equation. line through (x1, y1) and (x2, y2): x = x1 + t
Helen [10]

The parametric equations for the line passes through the points (X₁ , Y₁) and (X₂ , Y₂) are :

X = X₁ + t (X₂ - X₁) ......................... (1)

Y = Y₁ + t (Y₂ - Y₁) .......................... (2)

For eliminating the parameter (t) , first we will solve any one equation for 't' and then substitute that into another equation.

From the equation (1),

⇒ t = \frac{X- X1}{(X2 - X1)}

Substituting this t = \frac{X- X1}{(X2 - X1)} into the equation (2), we will get :

Y = Y₁ + \frac{(X- X1)}{(X2 - X1)} (Y₂ - Y₁)

Y = Y₁ + \frac{(X- X1)(Y2 - Y1)}{(X2 - X1)}

So, this is the standard form of rectangular equation.

For two given points (0, 0) and (4, -4)

X₁ = 0 , Y₁ = 0, X₂ = 4 and Y₂ = -4

For finding the parametric equations, we will plug these values into the given parametric equations.

X = X₁ + t (X₂ - X₁)

⇒ X = 0+ t (4 - 0)

⇒ X = 4t

and Y = Y₁ + t (Y₂ - Y₁)

⇒ Y = 0+ t (-4 - 0)

⇒ Y = - 4t

So, the parametric equations for the line passing through (0,0) and (4, -4) are: X = 4t and Y = -4t

6 0
3 years ago
What is the instantaneous velocity at t = 1 h?
satela [25.4K]

all you just have to do is divide 30 by 2 which is=15

and 40 by 4=10

50 by 10=5

ANSWER=15km/h

8 0
3 years ago
Read 2 more answers
2. Solve each given equation and show your work. Tell whether each equation has one solution, an infinite number of solutions, o
katrin2010 [14]
A is unsolvable because 4=0.
B can be solved.
C is infinite
8 0
3 years ago
Read 2 more answers
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