What is the common score amount all 100 gymnasts?

What are the solution

AleksandrR [38]

Answer:

B

Step-by-step explanation:

We can get two equations from the inequality:

$3x+2>9\\3x+2>-9$

We just need to simplify both equations to get our answers:

$3x+2>9\\3x>7\\x>\frac{7}{3}$

$3x+2>-9\\3x>-11\\x>\frac{-11}{3}$

The two answers we get are:

$x\frac{7}{3}$

Which is also B.

3 0

2 years ago

What is the vertices of hexagon<br>

nata0808 [166]

Number of vertices of hexagon is 6

5 0

3 years ago

Read 2 more answers

Points F(3, 3), K(6, 5), J(8, 2) and L(5, 0) lie in a coordinate plane. Which lines are perpendicular?

Romashka-Z-Leto [24]

To determine if a line is perpendicular to another, you must first determine the slope...
m = y1-y2/x1-x2
m of FK = 3-5/3-6 = -2/-3 = 2/3
m of FJ = 3-2/3-8 = 1/-5
m of FL = 3-0/3-5 = 3/-2
m of KJ = 5-2/6-8 = 3/-2
m of KL = 5-0/6-5 = 5
m of JL = 2-0/ 8-5 = 2/3

In order for two lines to be perpendicular, their slopes must be opposite reciprocals...
FK is perpendicular to FL
FK is perpendicular to KJ
JL is perpendicular to FL
JL is perpendicular to KJ
FJ is perpendicular to KL

8 0

3 years ago

Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen

Jobisdone [24]

Parameterize $S$ by the vector function

$\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k$

so that the normal vector to $S$ is given by

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}$

In this case, the normal vector is

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k$

with magnitude $\sqrt{1^2+2^2+1^2}=\sqrt6$ . The integral of $f(x,y,z)=e^z$ over $S$ is then

$\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx$

where $T$ is the region in the $x,y$ plane over which $S$ is defined. In this case, it's the triangle in the plane $z=0$ which we can capture with $0\le x\le8$ and $0\le y\le\frac{8-x}2$ , so that we have

$\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}$

5 0

3 years ago

kyra invested $400 at 3% for 3 years . lishshawn invested $500 at 4% for 2 years calculate who earn the most interest and how mu

eimsori [14]

Answer:

Okay, so a bit of math is involved, along with steps.

Step-by-step explanation:

Kyra invested $400 at 3% for 3 years. meaning 3% of $400 is 12. 400+12=

Year 1: $412

3% of 412=12.23+412=

Year 2: $424.23

3% of 424.23=12.7+423.23=

Year 3: $435.93

Kyra made $35.93 in investments.

Lishsawn invested $500 at 4% for 2 years. Meaning, 4% of $500 is 20. 500+20

Year 1: $520

4% of 520=20.8+520

Year 2: $540.8

Lishawn made $40.8 dollars in investments. Meaning that Lishawn made $4.87 more dollars

6 0

3 years ago