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3 years ago

What is the slope of (-1,3) and (3,1)

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

5 0

<h3>Answer: -1/2</h3>

Work Shown:

Apply the slope formula

m = (y2-y1)/(x2-x1)

m = (1-3)/(3-(-1))

m = (1-3)/(3+1)

m = -2/4

m = -1/2 is the slope

In decimal form, this converts to -0.5, though usually slopes are in fraction form.

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Answer all a,b,c,d,f

leonid [27]

Evaluating all the given expressions using the standard order of operations is as below

How to Evaluate Algebra Expressions?

We are given that;

x = -2

y = -3

z = 5

A) The algebraic equation 2x + 3y + z gives;

2(-2) + 3(-3) + 5 = -5

B) x - y gives;

-2 - (-3) = 1

C) 2(x + y)/z gives;

2(-2 - 3)/5 = -2

D) 3x² - 2x + 1

f(-2) = 3(-2)² - 2x + 1

f(-2) = 17

E) 3y(x + x² - y)

3(-3)(-2 + (-2)² - (-3))

-9 * 5 = -45

F) -z²(1 - 2x)/(y - x)

Thus;

-5²(1 - 2(-2))/(-3 - (-2))

= 625

Read more about Algebra Expressions at; brainly.com/question/4344214

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2 years ago

Can 24/7 be simplified into a smaller fraction?

dimaraw [331]

Answer:

Step-by-step explanation:

It can't because no number goes into 24 and 7, and 7 does not go its 24

6 0

3 years ago

Read 2 more answers

• Write the equation of the line that passes through the points (-7,0) and(-3,-9). Put your answer in fully reduced point-slope

coldgirl [10]

We want to calculate the line that passes through the points (-7,0) and (-3,-9). Recall that the equation of a line is

$y=mx+b$

where m is the slope and b is the y intercept. We can calculate first the slope and then find the value of b. To do so, recall that given points (a,b) and (c,d) the slope of the line that passes through them is given by the formula

$m=\frac{(d\text{ -b)}}{(c\text{ -a)}}=\frac{b\text{ -d}}{a\text{ -c}}$

so by taking a=-7, b=0, c=-3 and d=-9 we get

$m=\frac{0\text{ - (-9)}}{\text{ -7 -( -3)}}=\frac{9}{\text{ -4}}=\text{ -}\frac{9}{4}$

so our equation becomes

$y=\text{ -}\frac{9}{4}x+b$

so know we want this line to pass through the point (-7,0), so whenever x= -7 then y=0 so we have the equation

$0=\text{ -}\frac{9}{4}(\text{ -7)+b}$

or equivalently

$0=\frac{63}{4}+b$

so if we subtract 63/4 on both sides, we get

$b=\text{ -}\frac{63}{4}$

so our equation would be

$y=\text{ -}\frac{9}{4}x\text{ -}\frac{63}{4}$

3 0

1 year ago

Prove each of these identities.

Virty [35]

<h3>Answer:</h3>

➲ ( 1 + sec x )( cosec x - cot x ) = tan x

Solving for L.H.S

$\implies\quad \sf{(1+sec\:x)(cosec\:x-cot\:x) }$

$\implies\quad \sf{ \left(1+\dfrac{1}{cos\:x}\right)\left(\dfrac{1}{sin\:x}-\dfrac{cos\:x}{sin\:x}\right)}$

$\implies\quad \sf{ \left(\dfrac{1+cos\:x}{cos\:x}\right)\left(\dfrac{1-cos\:x}{sin\:x}\right)}$

$\implies\quad \sf{ \left(\dfrac{1-cos^2 x}{cos\:x.sin\:x}\right)}$

$\implies\quad \sf{ \left( \dfrac{sin^2 x}{cos\:x.sin\:x}\right)}$

$\implies\quad \sf{ \left( \dfrac{sin\:x.\cancel{sin\:x}}{cos\:x.\cancel{sin\:x}}\right)}$

$\implies\quad \sf{\left( \dfrac{sin\:x}{cos\:x}\right) }$

$\implies\quad\underline{\underline{\pmb{ \sf{tan\:x}}} }$

➲ ( 1+ sec x )( 1- cos x ) = sin x. tan x

Solving for L.H.S

$\implies\quad \sf{ ( 1+ sec\:x)(1-cos\:x)}$

$\implies\quad \sf{\left(1+\dfrac{1}{cos\:x} \right) \left( 1-cos\:x\right)}$

$\implies\quad \sf{ \left(\dfrac{cos\:x+1}{cos\:x} \right)(1-cos \:x)}$

$\implies\quad \sf{\dfrac{1-cos^2 x}{cos\:x} }$

$\implies\quad \sf{\dfrac{sin^2x}{cos\:x} }$

$\implies\quad \sf{sin\:x.\left( \dfrac{sin\:}{cos\:x}\right) }$

$\implies\quad\underline{\underline{\pmb{ \sf{sin\:x.tan\:x}}} }$

7 0

3 years ago

Can someone please give me the (Answers) to this? ... please ...

ahrayia [7]

A.) The SAS Triangle Congruence Postulate states that if if a pair of corresponding sides, a pair of corresponding angles, and another pair of corresponding sides in two triangles are congruent, then the two triangles are congruent. Therefore, we can see that in both triangles, we are only shown a corresponding, congruent right angle. We need two pairs of sides with the corresponding right angles to prove that the triangles are congruent via SAS. We would need to know the length of side VX, and it’s corresponding side length, XV. We would also need to know the side lengths of WV and it’s corresponding side length, XK. We would then need some sort of symbol to represent a congruent relationship if the side lengths are congruent. Then, we would have two pairs of corresponding, congruent sides, and a pair of corresponding, congruent angles. Then, we would have a Side-Angle-Side.

b.) We are given two triangles with a pair of corresponding, congruent sides. We need to have a pair of corresponding, congruent angles, another pair of corresponding, congruent sides to follow SAS. Therefore, we would need to know the angle measures of angles UVW and KVM. We know that they are vertical angles, so they are indeed congruent. Now, we would need to know the side lengths of sides WV and VM. If those sides are congruent, then we have a pair of corresponding, congruent sides, a pair of corresponding, congruent angles, and another pair of corresponding, congruent sides, making SAS.

c.) The Angle Side Angle Postulate states that if there is a pair of corresponding, congruent angles, a pair of corresponding, congruent sides, and another pair of corresponding, congruent angles in two triangles, then the two triangles are congruent. We have a pair of corresponding, congruent angles, a pair of corresponding, congruent sides, but we need another pair of congruent, corresponding angles. Therefore, we would need to know the angle measures of angles MLK and STU. Then we would have a a pair of corresponding, congruent angles, a pair of corresponding, congruent sides, and another pair of corresponding, congruent angles.

Please give Brainliest! This took a lot of time!

5 0

3 years ago

Read 2 more answers