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Elanso [62]
2 years ago
10

The ages of a bowling team are 33, 25, 39, and 37. Mary just joined the team and is 34 years old.

Mathematics
1 answer:
lidiya [134]2 years ago
4 0

Answer: 1. c 2. a 3. b 4.a 5.b 6.c Here we go

Step-by-step explanation:

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Multiplying a number by 4/5 then dividing by 2/5 is the same as multiplying what number?
prisoha [69]
Multiplying a number by 4/5 and then dividing by 2/5 is the same as multiplying by 2


5 0
3 years ago
Leslie decides to join a gym. She must pay a monthly fee plus a one time fee to open a membership. This situation can be modeled
omeli [17]

Step-by-step explanation:

Given function is,

y=55x+80

Where,

y = amount paid to the gym in dollars

x = number of months

So when x = 0, y =55(0)+80 = 80

i.e when number of months is 0, you have to pay a fee of $80.

This is the one time fee to open a membership.

After that for each month you have to pay $55 for each months.

So 55 is multiplied with x.

3 0
3 years ago
What is the equivalent ratio of 82:36?
Tom [10]

41:18

82 / 2 = 41

36 / 2 = 18

I hope this helps.

8 0
3 years ago
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Susan can buy 6 flower seed packets for $2. If all the seed packets cost the same amount of money, how many packets can Susan bu
antiseptic1488 [7]

Answer:She can buy 30 packets

Step-by-step explanation:

6 flower seeds  $2

12 flower seeds $4

18 flower seeds $6

24 flower seeds $8

30 flower seeds $10

8 0
3 years ago
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The first two numbers in a sequence h are h(1) = 2 and h(2) = 6.
Ghella [55]

Answer:

Step-by-step explanation:

Given the first two numbers of a sequence as 2, 6...

If it is an arithmetic difference, the common difference will be d = 6-2 = 4

Formula for calculating nth term of an ARITHMETIC sequence Tn = a+(n-1)d

a is the first term = 2

d is the common difference = 4

n is the number if terms

Substituting the given values in the formula.

Nth term Tn = 2+(n-1)4

Tn = 2+4n-4

Tn = 4n-4+2

Tn = 4n-2

2) If the sequence us a geometric sequence

Nth term of the sequence Tn = ar^(n-1)

r is the common ratio

r is gotten by the ratio of the terms I.e

r = T2/T1

r = 6/2

r = 3

Since a = 2

Tn = 2(3)^(n-1)

Hence the nth term of the geometric sequence is Tn = 2(3)^(n-1)

3 0
3 years ago
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