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Ghella [55]
3 years ago
10

A paper company needs to ship paper to a large printing business. The paper will be shipped in small boxes and large boxes. Each

small box of paper weighs 45 pounds and each large box of paper weighs 90 pounds. What would be the total weight, in pounds, of 6 small boxes and 10 large boxes? What would be the total weight, in pounds, of ss small boxes and ll large boxes?
6 small boxes and 10 large boxes:
s small boxes and l large boxes:
Mathematics
1 answer:
daser333 [38]3 years ago
5 0

Answer:

Small box: 270

Large box: 900

45s or 45·s

90l or 90·l

Step-by-step explanation:

45·6= 270

90·10=900

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PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer this correctly!!!! (80pts)
Valentin [98]

Answer:

I think its 57

Step-by-step explanation:

the difference of 6 divided by 2 is 3

i just divided 171 by 3 and got 57

3 0
3 years ago
Read 2 more answers
The price of a washing machine was decreased by 20% to £640.
pickupchik [31]

Answer:

£800

Step-by-step explanation:

Use the percentage formula: NV = m x OV

NV is New Value;

m is Multiplier;

and OV is Old Value.

£640 in the New value, so now we have to convert 20% to a multiplier and find out the Old value.

Make OV the subject of the formula: OV = NV / m

So 20% decrease would mean: 100 - 20 = 80 * 100 = 0.80

Divide 640 (NV) by 0.80 (m) and it will give you:

£800

And it would make sense that the OV is higher, and it matches the statement -> as the NV is the decrease.

5 0
3 years ago
What times 3 gives you 1,000
miv72 [106K]
1,000:3=\frac{1,000}{3}=333\frac{1}{3}\\\\Answer:\boxed{333\frac{1}{3}}\\\\check:\\\\333\frac{1}{3}\times3=\frac{1,000}{3}\times3=1,000
3 0
3 years ago
A jewelry stand sells 5 different pairs of earrings. The earrings sell for $12, $9, $6, $8, and $10.
Maslowich
The answer is $1.6

Step 1. Find the mean of all values (X = ?).
Step 2. Find the distance of all values from the mean (d1, d2, d3, d4, d5).
Step 3. Find the mean of distances (D).

x1 = $12
x2 = $9
x3 = $6
X4 = $8
x5 = $10

Step 1.
X = (x1 + x2 + x3 + x4 + x5)/5
    = (12 + 9 + 6 + 8 + 10)/5
    = 45/5
    = $9

Step 2.
d1 = 12 - 9 = 3
d2 = 9 - 9 = 0
d3 = 9 - 6 = 3
d4 = 9 - 8 = 1
d5 = 10 - 9 = 1

Step 3.
D = (d1 + d2 + d3 + d4 + d5)/5
    = (3 + 0 + 3 + 1 + 1)/5
    = 8/5
    = $1.6
3 0
3 years ago
Determine whether the series is convergent or divergent. 1 2 3 4 1 8 3 16 1 32 3 64 convergent divergent Correct:
Vanyuwa [196]

Answer:

This series diverges.

Step-by-step explanation:

In order for the series to converge, i.e. \lim_{n \to \infty} a_n =A it must hold that for any small \epsilon>0, there must exist n_0\in \mathbb{N} so that starting from that term of the series all of the following terms satisfy that  |a_n-A|n_0 .

It is obvious that this cannot hold in our case because we have three sub-series of this observed series. One of them is a constant series with a_n=1 , the other is constant with a_n=3 , and the third one has terms that are approaching infinity.

Really, we can write this series like this:

a_n=\begin{cases} 1 \ , \ n=4k+1, k\in \mathbb{N}_0\\ 2^{k}\ , \ n=2k, k\in \mathbb{N}_0\\3\ , \ n=4k+3, k\in \mathbb{N}_0\end{cases}

If we  denote the first series as b_n=1, we will have that \lim_{k \to \infty} b_k=1.

The second series is denoted as c_k=2^k and we have that \lim_{k \to \infty} c_k=+\infty.

The third sub-series d_k=3 is a constant series and it holds that \lim_{k \to \infty} d_k=3.

Since those limits of sub-series are different, we can never find such n_0\\ so that every next term of the entire series is close to one number.

To make an example, if we observe the first sub-series if follows that A must be equal to 1. But if we chose \epsilon =1, all those terms associated with the third sub-series will be out of this interval (A-1, A+1)=(0, 2).

Therefore, the observed series diverges.

5 0
4 years ago
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