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3 years ago

10

Tonya is creating a program that will allow the user to input their work address. Which kind of variable should Tonya use for th

is?
Select one:

a.
a syntax variable

b.
a float variable

c.
a string variable

d.
an alphabetic variable

2 answers:

Nady [450]3 years ago

5 0

Answer:

D. An alphabetic variable

Step-by-step explanation:

Marianna [84]3 years ago

3 0

Answer:

D

Step-by-step explanation:

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School band sold 30 raffle tickets each ticket is labeled with a number 1 to 31 winning ticket will be drawn what is the probabi

Setler [38]

Answer:

0.27

Step-by-step explanation:

To solve this problem, we will use Set Theory Approach to Probability.

Let U = the Sample Space which consists of all possible tests.

Of course U = {1,2,3 .... ,30}

So, no elements in that.

U = n = 30

Let Q = the event bearing a multiple of 4 No winning ticket, and,

R = the case that has the No. 19 winning ticket

∴

Q = { 4, 8, 12 , 16 , 20, 24 , 28} , and

R = {19} , so that

Q ∩ R = ϕ

P(Q ∩R ) = 0

As, n(Q) = 7 , n(R) = 1 , we have,

P (Q) = $\frac{n (A)}{n(U)}$ = $\frac{7}{30}$ , and P (R) = $\frac{1}{30\\}$

P (Q∪R) = P(Q ) + P(R) − P(A∩B) = $\frac{7}{30}$ + $\frac{1}{30\\}$ − 0 = $\frac{8\\}{30\\}$

≅ 0.27 .

4 0

3 years ago

"Why do whole numbers raised to an exponent get greater, while fractions raised to an exponent get smaller?" I completely unders

VARVARA [1.3K]

Say you have the fraction 1/2 to the power of 2, so 1/2^2. You could also write this down as: 1/2*(times)1/2 or 0,5*0,5. Whenever you multiply by a number smaller than one, the outcome will get smaller. Whenever you multiply by a number larger than one, the outcome will be larger.

8 0

3 years ago

△POQ~△ROS. Identify the coordinates of S and the scale factor. HELP ASAP!!

vodka [1.7K]

Answer:

S(-7,0) , 2/7

Step-by-step explanation:

To get coordinates of P we can see that

14*(2/7)=4

Now, to get coordinates of S, we have this equation :

$x*\frac{2}{7}=-2$

Multiply by 7 each side :

2x=-14

x=-7

y=0

8 0

4 years ago

How do you find the volume of the solid generated by revolving the region bounded by the graphs

d1i1m1o1n [39]

Answer:

About the x axis

$V = 4\pi[ \frac{x^5}{5}] \Big|_0^2 =4\pi *\frac{32}{5}= \frac{128 \pi}{5}$

About the y axis

$V = \pi [4y -y^2 +\frac{y^3}{12}] \Big|_0^8 =\pi *\frac{32}{3}= \frac{32 \pi}{3}$

About the line y=8

$V = \pi [64x -\frac{32}{3}x^3 +\frac{4}{5}x^5] \Big|_0^2 =\pi *(128-\frac{256}{3} +\frac{128}{5})= \frac{1024 \pi}{5}$

About the line x=2

$V = \frac{\pi}{2} [\frac{y^2}{2}] \Big|_0^8 =\frac{\pi}{4} *(64)= 16\pi$

Step-by-step explanation:

For this case we have the following functions:

$y = 2x^2 , y=0, X=2$

About the x axis

Our zone of interest is on the figure attached, we see that the limit son x are from 0 to 2 and on y from 0 to 8.

We can find the area like this:

$A = \pi r^2 = \pi (2x^2)^2 = 4 \pi x^4$

And we can find the volume with this formula:

$V = \int_{a}^b A(x) dx$

$V= 4\pi \int_{0}^2 x^4 dx$

$V = 4\pi [\frac{x^5}{5}] \Big|_0^2 =4\pi *\frac{32}{5}= \frac{128 \pi}{5}$

About the y axis

For this case we need to find the function in terms of x like this:

$x^2 = \frac{y}{2}$

$x = \pm \sqrt{\frac{y}{2}}$ but on this case we are just interested on the + part $x=\sqrt{\frac{y}{2}}$ as we can see on the second figure attached.

We can find the area like this:

$A = \pi r^2 = \pi (2-\sqrt{\frac{y}{2}})^2 = \pi (4 -2y +\frac{y^2}{4})$

And we can find the volume with this formula:

$V = \int_{a}^b A(y) dy$

$V= \pi \int_{0}^8 2-2y +\frac{y^2}{4} dy$

$V = \pi [4y -y^2 +\frac{y^3}{12}] \Big|_0^8 =\pi *\frac{32}{3}= \frac{32 \pi}{3}$

About the line y=8

The figure 3 attached show the radius. We can find the area like this:

$A = \pi r^2 = \pi (8-2x^2)^2 = \pi (64 -32x^2 +4x^4)$

And we can find the volume with this formula:

$V = \int_{a}^b A(x) dx$

$V= \pi \int_{0}^2 64-32x^2 +4x^4 dx$

$V = \pi [64x -\frac{32}{3}x^3 +\frac{4}{5}x^5] \Big|_0^2 =\pi *(128-\frac{256}{3} +\frac{128}{5})= \frac{1024 \pi}{5}$

About the line x=2

The figure 4 attached show the radius. We can find the area like this:

$A = \pi r^2 = \pi (\sqrt{\frac{y}{2}})^2 = \pi\frac{y}{2}$

And we can find the volume with this formula:

$V = \int_{a}^b A(y) dy$

$V= \frac{\pi}{2} \int_{0}^8 y dy$

$V = \frac{\pi}{2} [\frac{y^2}{2}] \Big|_0^8 =\frac{\pi}{4} *(64)= 16\pi$

6 0

3 years ago

What is 4/3 times 3/7=?

Sidana [21]

The answer is 4/7 in simplest form

3 0

3 years ago