Answer:
32
Step-by-step explanation:
77 quarters and dimes
q + d = 77
subtract q from both sides
d = 77 - q
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A collection of quarters and dimes is worth $12.50 (1250 cents)
25q + 10d = 1250
substitute for d
25q + 10(77 - q) = 1250
distribute
25q + 770 - 10q = 1250
Combine like terms
15q + 770 = 1250
subtract 770 from both sides
15q = 480
divide both sides by 15
q = 32
12 can go into 648 54 times. :)
Answer: The third and fourth problem are linear
Step-by-step explanation:
3rd problem follows a pattern
X 6 5 4 3
Y 21 15 10 6
6x3+3=21
5x3=15
4x2+2=10
3x2=6
Problem 4 follows a pattern as well
X value goes up 1, Y value goes up 4
Answer:
32
Step-by-step explanation:
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)
Given n(A)= ? we represent with x
n(B)= 16
n(A∪B) = 32
Substituting in equation 1 to get n(A)
32 = n(A) + 9 − 9
⇒n(A) = 32 − 0
n(A) = 32
to confirm this we put the values into the formula below
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)
32 = 32 + 9 - 9
Answer:
The answer would be C) 64 and 112
Step-by-step explanation:
If you go through each answer and find which perimeters they would have, you would get 108 for A, 312 for B, 352 for C, and 372 for D. The question says the perimeter is equal to 352 therefore C is the answer.
