Hello There!
All you really need to do is multiply 160 with 32.

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5120 cm
Hope this helped!
Answer:


Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the grade points avergae of a population, and for this case we know the following properties
Where
and
The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).
So we can find the z score for the value of X=3.44 in order to see how many deviations above or belowe we are from the mean like this:

So the value of 3.44 is 2 deviations above from the mean, so then we know that the percentage between two deviations from the mean is 95% and on each tail we need to have (100-95)/2 = 2.5% , because the distribution is symmetrical, so based on this we can conclude that:

Don’t use that link!! They always comment under my stuff and other people have told me that’s just to get your information and location and stuff like that! Be safe and have a nice day
Answer:
the answer should be D
Step-by-step explanation:
:)
Answer:
{0, 3, 12}
Step-by-step explanation:
Put the domain values in the function and evaluate. The result is the range values.
y = 3{-2, -1, 0}^2 = 3{4, 1, 0} = {12, 3, 0}
For the given domain, the range is {0, 3, 12}.
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<em>Additional comment</em>
Neither the domain nor range values need to be put in any particular order. However, it is often convenient for them to be arranged from least to greatest.