Let's say the numbers are "a" and "b"
thus

set the derivative to 0, and check the critical points, there's only one anyway
and do a first-derivative test, to see if it's a maximum
Answer:
78 sqr units
Step-by-step explanation:
Use the Pythagorean Theorem to help find the base opposite the two.
The base of the second parallel line is sqrt( (15^2) - (12^2) ) = sqrt(81) = 9
The second base = 9 + 2 = 11
Area = (b1 + b2)*h/2
h = 12
b1 = 2
b2 = 11
h = 12
Area = (11 + 2)*12/2
Area = 13 * 12/2
Area = 78 square units
Answer:
- x = 30°
- RS = 30°, SR = TU = 120°, UR = 90°
- ∠P = 45°
- ∠UTS = 60°
Step-by-step explanation:
(a) If RS = x, then the sum of arcs around the circle is ...
x + 4x +4x +3x = 360°
12x = 360°
x = 30°
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(b) Based on the given ratios, the arc measures are computed from x. For example, ST = TU = 4x = 4(30°) = 120°
- RS = 30°
- ST = 120°
- TU = 120°
- UR = 90°
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(c) Angle P is half the difference of arcs TU and RS:
∠P = (TU -RS)/2 = (120° -30°)/2
∠P = 45°
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(d) Inscribed angle UTS is half the measure of the arc it intercepts. Arc RU has the measure (30° +90°) = 120°, so the measure of UTS is ...
∠UTS = 120°/2 = 60°
Answer:
D. Minimum at (3, 7)
Step-by-step explanation:
We can add and subtract the square of half the x-coefficient:
y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2
y = (x -3)^2 +7 . . . . . simplify to vertex form
Comparing this to the vertex for for vertex (h, k) ...
y = (x -h)^2 +k
We find the vertex to be ...
(3, 7) . . . . vertex
The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.
Q: What is the equation of the exponential curve that passes through the points (0,3) and (5, 96)?
Answer: y=3 (2)x