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Answer:
The number of games for Xbox is about 155
The number of games for PS4 is about 175
Step-by-step explanation:
Let us find the numbers of games for Xbox and for PS4 game
∵ There are 330 video games in the store
∵ 47% of them were for Xbox
- Multiply 47% by 330
∴ The number of games for Xbox = 47% × 330
∵ 47% =
∴ The number of games for Xbox = × 330
∴ The number of games for Xbox = 155. 1
∴ The number of games for Xbox ≅ 155
∵ 53% of them were for PS4
- Multiply 53% by 330
∴ The number of games for PS4 = 53% × 330
∵ 53% =
∴ The number of games for PS4 = × 330
∴ The number of games for PS4 = 174.9
∴ The number of games for PS4 ≅ 175
I'm going to assume that the room is a rectangle.
The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle.
You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:
Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:
Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.
The dimensions of your room are 25ft (length) by 24ft (width).
The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle.
You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:
Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:
Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.
The dimensions of your room are 25ft (length) by 24ft (width).