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liraira [26]
3 years ago
15

I don’t know the answer

Mathematics
1 answer:
ale4655 [162]3 years ago
8 0

Answer:

I think it is B. 30 degrees

Step-by-step explanation:

Because if ZUY is 90 degrees and half of 90 degrees is 45 degrees but TUZ is a little bit less than the middle part of ZUY it has to be less than 45 degrees by a little bit and the only option would be 30 degrees. Hope this helped (:

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Let us assume the number of student's in Zoe's class = x
Then
Number of students that have pets = 4x/5
Number of students that have rodents as pets = (1/8) * (4x/5)
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Number of students in Zoe's class
that have pets that are not rodents = (4x/5) - (x/10)
                                                         = (8x - x)/10
                                                         = 7x/10
I hope that the procedure is clear enough for you to understand and this is the answer that you were looking for.
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A wooden plaque is in the shape of an ellipse with height 26 centimeters and width 16 centimeters. Find an equation for the elli
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Step-by-step explanation:

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Fill in the blank: In data analytics, a _____ refers to all possible data values in a certain dataset
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In data analytics, a p<u>opulation </u>refers to all possible data values in a certain dataset

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6 0
2 years ago
A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
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